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CorollaryStatement: AI-adaptedProof: AI-generatedprecheck passverified 2026-09-23 (gpt-6-sol)
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  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
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Every open subset of a manifold is the cozero set of a smooth function

Statement

Assume the Axiom of Countable Choice. Every open subset U of a smooth manifold M is the cozero set of a smooth function on M.

Facts & Assumptions

Given: Countable Choice and an open set U⊆M.

[L1]

Under Countable Choice, every closed subset of a manifold is the zero set of a smooth nonnegative function (Every closed subset of a manifold is the zero set of a smooth nonnegative function).

Proof

technique · direct
1.1given

The complement A:=M∖U is closed.

2.1L1step 1.1

By [L1], there is a smooth nonnegative function g with A=g−1(0), so U={x:g(x)≠0}.

3.1step 2.1∎

Hence U is a smooth cozero set.

Depends on

Used by

Nothing in the library uses this result yet.

Dependency tree · two levels

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Sources