Alphabeta Math
CorollaryStatement: AI-adaptedProof: AI-adaptedPipeline-generatedjudge pass (gpt-5.6-terra)audited 2026-09-07
How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

Explicit polynomial time constant degree expanders exist

Statement

There is a uniform polynomial-time algorithm producing, for each positive vertex count N, a degree-128 expander HN with absolute nontrivial norm at most 1−49/1638400. The output has 128N adjacency slots; its bit-time cost is polynomial in N.

Facts & Assumptions

Given: the objects and hypotheses in the statement above.

[F1]

For every integer N≥1 there is a polynomial-time constructible reverse-paired 128-regular multigraph HN on exactly N vertices with α(HN)≤ρ0:=1−491638400<1. For N≥2 every S satisfies cut⁡(S)≥(7/10)min⁡(∣S∣,N−∣S∣). Every vertex has loops. (Expander size adjustment and laziness).

Proof

1.1F1

Apply the all-size construction at the given N. Its bound is independent of N and is strictly smaller than one. For N≥2 its unnormalized expansion is at least 7/10, so normalized expansion is at least 7/1280.

2.1F1step 1.1∎

The construction explicitly lists 128 destinations at each of the N vertices and runs in polynomial bit time. The singleton output has only loops and satisfies the zero-space spectral convention. Endpoint names require logarithmically many bits, so the adjacency-slot count alone is not a claim of linear bit time.

Depends on

Used by

Dependency tree · two levels

3 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources