Alphabeta Math
CorollaryStatement: Literature-sourcedProof: Literature-sourcedprecheck passaudited 2026-08-11
How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

An integrable function whose sections vanish outside finite sets has multiple integral zero

Statement

Let A⊆Rp and B⊆Rq be nondegenerate closed rectangles, and let f:A×B→R be Riemann integrable. If the set S:={x∈A:fx is not identically 0} is finite, then ∫A×Bf=0. The analogous assertion holds with the coordinate blocks exchanged.

Facts & Assumptions

Given: An integrable f:A×B→R whose nonzero B-sections are indexed by a finite set S.

[L1]

Riemann--Fubini permits a content-zero exceptional set of parameters and identifies the multiple integral with the resulting iterated integral (Riemann--Fubini on product rectangles, with lower and upper section integrals and content-zero exceptional sections).

[L2]

A set has content zero when it admits finite cube covers of arbitrarily small total volume (Measure zero and content zero in Rm by countable and finite cube covers).

Proof

technique · direct
1.1

A finite subset of Rp has content zero by [L2]: for a given ε>0, cover its finitely many points by cubes whose total volume is below ε.

L2given
2.1

Outside S every section is identically zero and has integral zero. Complete the section-integral function by the value 0 on S and apply [L1]; the resulting outer function is identically zero, so the multiple integral is zero.

L1step 1.1
3.1

If S is empty then f itself is identically zero, and step 2.1 still applies. Exchanging the coordinate blocks proves the symmetric assertion.

step 2.1algebra∎

Depends on

Used by

Nothing in the library uses this result yet.

Dependency tree · two levels

13 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources