Alphabeta Math
CorollaryStatement: Literature-sourcedProof: AI-adaptedPipeline-generatedprecheck passjudge pass (gpt-5.6-terra)audited 2026-09-07
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  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
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A continuous Fourier series supported on a Sidon set has ell-one coefficients

Statement

Let EZ be Sidon, and let f be continuous and one-periodic with f^(k)=0 for kE. Then

kEf^(k)<.

The finite Sidon inequality is the definition in Sidon sets in the integer dual. The Fejer kernels are positive and have mass one by The Fejer kernel is a positive approximate identity, and their means converge uniformly for this f by Fejer means converge uniformly for continuous periodic functions.

Facts & Assumptions

Given: E,f, and a Sidon constant CE as in the Statement.

Proof

technique · apply the finite Sidon inequality to Fejer polynomials and pass to monotone coefficient sums
1.1

The N-th Fejer mean is the finite polynomial [given, algebra] σNf=kN(1kN+1)f^(k)ek. Its spectrum lies in E. Positivity and mass one of the Fejer kernel give σNff.

givenalgebra
2.1

Apply the Sidon inequality to this polynomial: [step 1.1, algebra] kEkN(1kN+1)f^(k)CEf. For every fixed finite subset of E, the displayed weights tend monotonically to 1.

step 1.1algebra
3.1

Letting N first for each finite subset and then taking the [step 2.1, algebra] supremum over finite subsets gives kEf^(k)CEf. Uniform Fejer convergence identifies the same continuous function with these means, so no separate representative is introduced.

step 2.1algebra

Depends on

Used by

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