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CorollaryStatement: AI-adaptedProof: AI-adaptedPipeline-generatedjudge pass (gpt-5.6-terra)audited 2026-09-07
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Stokes agrees with the fundamental theorem of calculus

Statement

Assume ACω. For a<b, orient [a,b] increasingly. Every smooth f on this interval satisfies [a,b]df=f(b)f(a), where the boundary point signs are 1 at a and +1 at b. This agrees with the Riemann fundamental theorem of calculus.

Facts & Assumptions

[F1]

The general Stokes theorem: Assume ACω. Let M be an oriented smooth n-manifold with boundary, n1, and let ηΩcn1(M). With j:MM and the outward-normal-first orientation, Mdη=Mjη. An empty boundary contributes zero; in dimension one its integral is a finite signed sum of point values.

[F2]

Newton–Leibniz needs only continuity on [a,b], differentiability on (a,b), and a Riemann-integrable extension of the interior derivative: Let a<b. Suppose G:[a,b]R is continuous on [a,b] and differentiable on (a,b). If f:[a,b]R is Riemann integrable and f(x)=G(x)(a<x<b), then abf=G(b)G(a). No derivative of G at either endpoint is assumed, and the two endpoint values assigned to the integrable extension f do not enter the conclusion.

Proof

Given: The objects and hypotheses in the statement above.

1.1

The interval is compact, and the outward directions are t at a and +t at b. Outward-first gives the point signs 1,+1. Stokes therefore yields the difference f(b)f(a), including constant and zero functions.

F1
2.1

In its increasing coordinate, df=f(t)dt, so the left side is the ordinary Riemann integral of f. The published FTC applies: f is continuous on the closed interval and differentiable inside, and its smooth derivative is Riemann integrable. It gives the same endpoint difference. The condition a<b avoids treating a point as a one-manifold.

F2step 1.1

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