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CorollaryStatement: AI-generatedProof: AI-generatedSession-authored (Fable 5 assisted)precheck passaudited 2026-08-11
How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

The generator map XW(X)/X\to W(X)/{\sim} is injective

Statement

The generator map iword:XFword(X)i_{\mathrm{word}}:X\to F_{\mathrm{word}}(X) of The word-quotient group W(X)/W(X)/{\sim} satisfies the universal property of the free group on XX, given by iword(x)=[x]i_{\mathrm{word}}(x)=[x], is injective.

Facts & Assumptions

Given: Elements x,yXx,y\in X with [x]=[y][x]=[y] in Fword(X)F_{\mathrm{word}}(X).

[L1]

Every class in W(X)/W(X)/{\sim} contains exactly one reduced word (Every class in W(X)/W(X)/{\sim} contains exactly one reduced word).

Proof

technique · direct
1.1

The one-letter words xx and yy are reduced and lie in the same class, so uniqueness in [L1] gives x=yx=y.

L1given
2.1

Thus iword(x)=iword(y)i_{\mathrm{word}}(x)=i_{\mathrm{word}}(y) implies x=yx=y, which is injectivity; when XX is empty the assertion is vacuous.

step 1.1

Depends on

Used by

Nothing in the library uses this result yet.

Dependency tree · next 3 levels

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