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CorollaryStatement: Literature-sourcedProof: AI-adaptedPipeline-generatedjudge pass (gpt-5.6-terra)audited 2026-09-14
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Every uncountable cardinal is singular in Gitik's model

Statement

The model NG satisfies that every uncountable cardinal κ has cf(κ)=ω and is therefore singular.

Facts & Assumptions

Given: The completed Gitik symmetric model.

[F1]

Gitik's symmetric submodel satisfies ZF: NG satisfies ZF, without assuming Choice.

[F3]

Every limit ordinal has cofinality omega in Gitik's model: Every nonzero limit ordinal of NG has cofinality ω.

[F4]

Cardinal (initial ordinal) and cardinality and Cofinality cf(α), and regular and singular cardinals: An infinite cardinal is singular exactly when its cofinality differs from the cardinal.

Proof

1.1

Work inside NG, which satisfies ZF by F1, and let κ be an uncountable cardinal. Then κ is infinite, so F2 makes it a limit ordinal; it is nonzero because 0 is finite. F3 therefore gives cf(κ)=ω.

F1F2F3
2.1

Uncountability says ω<κ, so the equality from step 1.1 gives cf(κ)κ. By F4, κ is singular. The only excluded endpoint is ω itself: it is countable and regular, so the corollary neither includes nor misclassifies it. No Choice principle is used.

F4step 1.1

Depends on

Used by

Dependency tree · two levels

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Sources