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CorollaryStatement: Literature-sourcedProof: AI-adaptedprecheck passjudge pass (gpt-5.6-terra)audited 2026-08-26
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Two harmonic conjugates differ by a real constant

Statement

Let Ω be a complex domain, let u:Ω→R be harmonic, and let v1,v2 be harmonic conjugates of u on Ω. Then v1−v2 is a real constant on Ω.

Facts & Assumptions

Given: Harmonic conjugates v1,v2 of the same harmonic function u on a domain Ω.

[L1]

By definition, u+iv1 and u+iv2 are holomorphic on Ω (Harmonic conjugates).

[L2]

Sums, differences, and scalar multiples of holomorphic functions are holomorphic (Linearity, product, reciprocal, and quotient rules for complex derivatives).

[L3]

A real-valued holomorphic function on a domain is constant (A real-valued holomorphic function on a domain is constant).

Proof

technique · direct
1.1L1L2algebra

By [L1], the functions F1:=u+iv1 and F2:=u+iv2 are holomorphic, so [L2] makes −i(F1−F2)=v1−v2 holomorphic on Ω.

2.1step 1.1L3∎

The function v1−v2 is real-valued, so [L3] makes it constant on Ω.

Depends on

Used by

Dependency tree · two levels

9 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources