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Holomorphic functional calculus in the Wiener algebra

Statement

Assume the Axiom of Choice. Let fA(T) and let Φ be holomorphic on an open neighbourhood of f(T). Then ΦfA(T).

Facts & Assumptions

Given: The Axiom of Choice, fA(T), and Φ holomorphic near the compact set f(T).

[L1]

A nowhere-zero member of A(T) has its reciprocal in A(T) (Wiener's lemma for absolutely convergent Fourier series).

[L2]

A(T) is complete and closed under multiplication (The Wiener algebra is a unital commutative Banach algebra).

[L3]

Cauchy's formula holds for null-homologous complex cycles (Cauchy's integral formula for a null-homologous cycle ).

Proof

technique · direct
1.1

Let Ω be an open set on which Φ is holomorphic and which contains f(T). The compact-neighbourhood lemma A compact subset of an open Euclidean set has a compact Jordan neighborhood inside that open set gives a finite union J of closed grid rectangles with f(T)intJJΩ. Orient the frontier edges of the constituent grid cells positively and cancel each internal edge against its reverse. The resulting polygonal chain Γ is a cycle in Ωf(T), with n(Γ,w)=1 for wf(T) and n(Γ,w)=0 for wΩ: summing the cell indices first proves this away from the grid lines, and local constancy of the cycle index extends it to every point off the frontier. Thus Γ is null-homologous in Ω. For zΓ, zf has no zero on T, so (zf)1A(T) by [L1].

L1givenchoosealgebra
2.1

The map zΦ(z)(zf)1 is continuous into A(T) (the inverse identity follows from (zf)1(wf)1=(wz)(zf)1(wf)1). Hence its normalized chain integral F:=12πiΓΦ(z)(zf)1dz is an A(T) element, as the finite sum of norm-limits of edgewise Riemann sums by [L2].

L2step 1.1algebra
3.1

Evaluation at x commutes with those norm-limits. Since step 1.1 gives n(Γ,f(x))=1 and makes Γ null-homologous in Ω, [L3] applied to Φ gives F(x)=Φ(f(x)). Thus F=Φf and belongs to A(T).

L3step 1.1step 2.1

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