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CorollaryStatement: Literature-sourcedProof: AI-adaptedprecheck passjudge pass (deepseek-v4-pro + claude-opus-5[1m])audited 2026-08-24
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The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

An injective holomorphic map has no critical point and is biholomorphic onto its image

Statement

An injective holomorphic map on a complex domain has nowhere-zero derivative and is biholomorphic onto its open image.

Precisely, if f:Ω→C is holomorphic and injective on a complex domain, then f′(a)≠0 for every a∈Ω, the set f[Ω] is a complex domain, and f:Ω→f[Ω] is biholomorphic (Biholomorphic maps between complex domains).

Facts & Assumptions

Given: A holomorphic injective map f:Ω→C on a complex domain. Injectivity and bijectivity have their set-theoretic meanings (Injection, surjection, bijection).

[L1]

If f is nonconstant and holomorphic on a complex domain Ω and a∈Ω, then f′(a)≠0, deg⁡af=1, local injectivity at a, and biholomorphy between neighbourhoods of a and f(a) are equivalent (Holomorphic inverse function theorem and local-degree criterion).

[L2]

Every nonconstant holomorphic function on a complex domain is an open map (Open mapping theorem for holomorphic functions).

[L3]

A complex differentiable function is continuous at every point of complex differentiability (Complex differentiability at a point implies continuity there).

[L4]

A continuous image of a connected space is connected (A continuous image of a connected space is connected, and connectedness is a topological property, claim 1).

Proof

technique · direct
1.1L1given

The map f is nonconstant because an open complex domain has distinct points and f is injective. It is locally injective at every a∈Ω, so [L1] gives f′(a)≠0 and a holomorphic local inverse near f(a).

1.2L2L3L4given

By [L2], the image f[Ω] is open. By [L3], f is continuous, so [L4] makes its image connected; it is therefore a complex domain.

2.1step 1.1step 1.2

The global set-theoretic inverse f−1:f[Ω]→Ω agrees near every image point with the holomorphic local inverse from step 1.1. Hence f−1 is holomorphic throughout the image.

3.1step 2.1∎

The map f is bijective onto its image, and step 2.1 makes its inverse holomorphic; therefore it is biholomorphic onto the open image.

Depends on

Used by

Dependency tree · two levels

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Sources