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CorollaryStatement: AI-adaptedProof: AI-generatedprecheck passaudited 2026-08-21
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  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
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An injective regular Ck map is a Ck diffeomorphism onto its image

Statement

Let k,n≥1, let U⊆Rn be open, and let f:U→Rn be an injective Ck map whose derivative is invertible everywhere. Then f[U] is open and the corestriction f:U→f[U] is a Ck diffeomorphism.

Facts & Assumptions

Given: The hypotheses in the Statement and the Ck diffeomorphism convention of Ck Euclidean maps and diffeomorphisms.

[L1]

Under the corresponding C1 hypotheses, f[U] is open and f:U→f[U] is a C1 diffeomorphism (An injective regular C1 map is a diffeomorphism onto its image).

[L2]

If f is Ck for k≥1, then every local inverse supplied by the inverse function theorem is Ck (A local inverse of a Ck regular map is Ck).

Proof

technique · direct
1.1L1

Since a Ck map with k≥1 is C1, [L1] supplies the open image and the unique global C1 inverse g:f[U]→U.

2.1step 1.1L2∎

Around each y∈f[U], the inverse g agrees with the unique local inverse of f. By [L2] that restriction is Ck. Thus g is locally, and hence globally, Ck, so the corestriction is a Ck diffeomorphism.

Depends on

Used by

Dependency tree · two levels

13 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources