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Lebesgue measure is the Lebesgue-Stieltjes measure of the identity function
Statement
Assume the Axiom of Countable Choice. Let . The Lebesgue-Stieltjes measure attached to agrees with Lebesgue measure from Lebesgue measurable sets, the family , and the restricted set function on every Borel subset of .
Facts & Assumptions
Given: Countable choice and the identity function .
Assuming countable choice, every nondecreasing right-continuous function on defines a Borel measure through the Lebesgue-Stieltjes construction. (Assuming countable choice, a nondecreasing right-continuous function defines a Borel measure on )
For every half-open interval , Lebesgue measure satisfies . (A box in with parameters is Lebesgue measurable of measure , whichever of its faces are included)
A Borel measure on finite on compact sets is uniquely determined by its values on half-open intervals. (The interval data on determines the Borel measure uniquely)
Proof
The identity function is nondecreasing and right-continuous, so [L1] gives a Borel measure with
[L1]
By [L2], Lebesgue measure has the same half-open interval values: for every .
The measures and are both Borel and finite on compact sets, and by steps 1.1 and 1.2 they agree on every half-open interval.
Therefore [L3] gives . [step 1.1, step 1.2, L3] ∎
Depends on
- Lebesgue measurable sets, the family $\mathcal{L}(\mathbb{R}^n)$, and the restricted set function $\lambda_n$
- Assuming countable choice, a nondecreasing right-continuous function defines a Borel measure on $\mathbb{R}$
- A box in $\mathbb{R}^n$ with parameters $a_i\le b_i$ is Lebesgue measurable of measure $\prod_{i<n}(b_i-a_i)$, whichever of its faces are included
- The interval data on $(a,b]$ determines the Borel measure uniquely
Used by
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Sources
- John K. Hunter, Measure Theory, Example 2.35 (standard reference, not scraped)