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Assuming countable choice, a nondecreasing right-continuous function defines a Borel measure on
Statement
Assume the Axiom of Countable Choice. Let be nondecreasing and right-continuous. Then there is a Borel measure on , finite on compact sets in the sense of A Borel measure on that is finite on compact sets, such that
Facts & Assumptions
Given: Countable choice, a nondecreasing right-continuous function , and its interval set function on the half-open interval algebra.
The interval set function is a premeasure on the half-open interval algebra. (The Stieltjes interval set function is a premeasure)
Assuming countable choice, a premeasure extends to a measure on the sigma-algebra it generates. (Assuming countable choice, a premeasure extends through its induced outer measure)
The family of half-open intervals with generates the Borel sigma-algebra . (Seven generating families for the Borel sigma-algebra on the real line)
A compact subset of is bounded. (A compact subset of is closed and bounded)
Proof
By [L1], is a premeasure, so [L2] gives a measure on the generated sigma-algebra extending .
By [L3], that sigma-algebra is , and therefore
for every . [L1, L2, L3]
Let be compact. By [L4] there is with .
So monotonicity and step 1.1 give
Thus is finite on compact sets. [step 1.1, L4, algebra]
The measure of steps 1.1 and 2.1 is therefore a Borel measure on finite on compact sets and having the prescribed half-open interval values.
This is the required . [step 1.1, step 2.1] ∎
Depends on
- A Borel measure on $\mathbb{R}$ that is finite on compact sets
- Assuming countable choice, a premeasure extends through its induced outer measure
- Seven generating families for the Borel sigma-algebra on the real line
- The Stieltjes interval set function is a premeasure
- A compact subset of $\mathbb{R}$ is closed and bounded
Used by
- Lebesgue measure is the Lebesgue-Stieltjes measure of the identity function Corollary
- The Cantor measure Definition
- The arctangent distribution function generates a Borel probability measure Example
- FALSE: a Lebesgue-Stieltjes measure always gives every singleton measure 0 False statement
- Assuming countable choice, finite-on-compacts Borel measures on ℝ correspond to nondecreasing right-continuous functions modulo constants Theorem
Dependency tree · two levels
37 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.
Sources
- Gerald B. Folland, Real Analysis, 2nd ed., Theorem 1.16 (standard reference, not scraped)
- John K. Hunter, Measure Theory, Theorem 2.34 (standard reference, not scraped)