Alphabeta Math
CorollaryStatement: AI-adaptedProof: AI-generatedjudge pass (gpt-5.6-terra)audited 2026-09-04
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The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

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The critical level is a quadratic cone in Morse coordinates

Statement

Let f:MR be smooth, let p be a nondegenerate critical point of index λ on an n-manifold, and choose Morse coordinates around p. Then near p the critical level set is

f1(f(p))={i=1λ(xi)2=i=λ+1n(xi)2}.

If λ=0 or λ=n, this local level set is just the point p.

Facts & Assumptions

Given: A smooth function f:MR and a nondegenerate critical point p of index λ.

[L1]

In Morse coordinates, ff(p)=i=1λ(xi)2+i=λ+1n(xi)2. (Morse lemma)

Proof

technique · normal form reading
1.1

By [L1], the equation f=f(p) becomes i=1λ(xi)2=i=λ+1n(xi)2.

L1givenalgebra
2.1

If λ=0, the left-hand side is the empty sum 0, so the equation is 0=i=1n(xi)2, which forces x=0. If λ=n, the right-hand side is the empty sum and the same conclusion follows.

step 1.1algebra
3.1

Therefore the local critical level is the stated quadratic cone, with the index-0 and index-n cases collapsing to the single critical point.

step 1.1step 2.1

Depends on

Used by

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Dependency tree · two levels

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