Alphabeta Math
CorollaryStatement: AI-adaptedProof: AI-adaptedSession-authored (Fable 5 assisted)precheck passjudge pass (deepseek-v4-pro + gpt-5.6-terra)audited 2026-08-13
How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

A localisation is unique up to a unique isomorphism compatible with the map from R

Statement

Let λ:RL and λ:RL be unital homomorphisms of commutative rings. Suppose each map sends every sS to a unit and has the localisation universal property: every homomorphism from R that inverts S factors uniquely through it. Then there is a unique ring isomorphism Φ:LL such that Φλ=λ.

Facts & Assumptions

Given: Two objects (L,λ) and (L,λ) satisfying the stated universal property for the same pair (R,S).

[F1]

A homomorphism from R that takes S to units factors uniquely through a localisation map (Universal property of localisation: maps that invert S factor uniquely through S1R).

Proof

technique · direct universal-property argument
1.1

Apply the universal property of L to λ and that of L to λ. This gives unique homomorphisms Φ:LL and Ψ:LL with Φλ=λ and Ψλ=λ.

F1
2.1

Both ΨΦ and idL compose with λ to give λ. Uniqueness for L gives ΨΦ=idL; similarly ΦΨ=idL. Thus Φ is an isomorphism.

F1step 1.1
3.1

Any isomorphism compatible with the maps from R is, in particular, a factorisation of λ through λ, so it equals Φ by uniqueness.

F1step 1.1

Depends on

Used by

Dependency tree · next 3 levels

Direct dependencies and their dependencies through the next three levels: 16 results over 12 levels. An arrow runs from a result to what uses it, and this result sits at the bottom with a heavier outline. Click the chart to enlarge it.

Sources