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CorollaryStatement: AI-adaptedProof: AI-adaptedprecheck passverified 2026-08-02 (claude-opus-5)
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The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

Addition is a well-defined total operation

Statement

For each m∈N there is a unique function sm:N→N with sm(0)=m and sm(σ(n))=σ(sm(n)). Writing m+n:=sm(n), addition +:N×N→N is a well-defined total binary operation satisfying m+0=m and m+σ(n)=σ(m+n).

Facts & Assumptions

Given: the natural numbers N with successor σ.

[L1]

The recursion theorem: for a set A, an element a∈A, and a function f:A→A there is a unique g:N→A with g(0)=a and g(σ(n))=f(g(n)) (The recursion theorem).

[L2]

(N,0,σ) is a Peano system (The von Neumann naturals form a Peano system).

Proof

technique · direct
1.1

Fix m∈N; since (N,0,σ) is a Peano system [L2], apply the recursion theorem with A=N, a=m, and f=σ: there is a unique function sm:N→N with sm(0)=m and sm(σ(n))=σ(sm(n)).

L1L2
2.1

Define m+n:=sm(n); since sm is a total function on N for every m∈N, the assignment (m,n)↦m+n is a well-defined function N×N→N.

step 1.1
3.1

The recursion equations become m+0=sm(0)=m and m+σ(n)=sm(σ(n))=σ(sm(n))=σ(m+n), the defining clauses of addition.

step 1.1step 2.1∎

Depends on

Used by

Dependency tree · two levels

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Sources