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TheoremStatement: Literature-sourcedProof: AI-adaptedprecheck passjudge pass (openai/gpt-5.4)audited 2026-07-25
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The von Neumann naturals form a Peano system

Statement

The triple (N,0,σ)=(ω,∅,⋅+) satisfies the three Peano axioms (Peano system): (P1) σ(n)≠0 for all n; (P2) σ is injective; (P3) induction. Hence a Peano system exists.

Facts & Assumptions

Given: N=ω, 0=∅, σ(n)=n∪{n} (The natural numbers N (von Neumann)).

[L1]
[L2]

Every natural number is transitive and satisfies n∉n (Every natural number is a transitive set and is not a member of itself).

Proof

technique · direct
1.1

(P3) The induction axiom holds: it is exactly the induction principle.

L1
1.2

(P1) For every n, σ(n)=n∪{n} contains n, so σ(n) is nonempty and σ(n)≠∅=0.

given
1.3

(P2) Suppose σ(m)=σ(n), i.e. m∪{m}=n∪{n}; then m∈n∪{n} so m∈n or m=n, and symmetrically n∈m or n=m; if m≠n then m∈n and n∈m, whence by transitivity [L2] m∈n gives m⊆n, and n∈m⊆n gives n∈n, contradicting n∉n [L2]; therefore m=n and σ is injective.

L2given
2.1

P1, P2, P3 all hold, so (N,0,σ) is a Peano system; in particular a Peano system exists.

step 1.1step 1.2step 1.3∎

Depends on

Used by

Dependency tree · two levels

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