Alphabeta Math
LemmaStatement: Literature-sourcedProof: AI-adaptedSession-authored (Fable 5 assisted)precheck passjudge pass (openai/gpt-5.4)audited 2026-07-25
How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced — the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted — a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated — a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

Addition is cancellative

Statement

For all m,n,kNm, n, k \in \mathbb{N}: if m+k=n+km + k = n + k then m=nm = n.

Facts & Assumptions

Given: Addition (Addition of natural numbers).

[L1]

σ\sigma is injective (P2) (The von Neumann naturals form a Peano system).

[L2]

Proof

technique · induction
1.1

Base k=0k = 0: if m+0=n+0m + 0 = n + 0 then m=nm = n, since m+0=mm + 0 = m and n+0=nn + 0 = n.

base
1.2

Inductive hypothesis: for all m,nm, n, m+k=n+km=nm + k = n + k \Rightarrow m = n.

ih
2.1

Step: suppose m+σ(k)=n+σ(k)m + \sigma(k) = n + \sigma(k); then σ(m+k)=σ(n+k)\sigma(m + k) = \sigma(n + k) by m+σ(j)=σ(m+j)m + \sigma(j) = \sigma(m + j), so m+k=n+km + k = n + k by injectivity [L1], hence m=nm = n by the hypothesis.

step 1.2L1
3.1

By induction [L2], cancellation holds for all kk, hence for all m,n,kNm, n, k \in \mathbb{N}.

step 1.1step 2.1discharge-induction

Depends on

Used by

Dependency tree · next 3 levels

Direct dependencies and their dependencies through the next three levels: 18 results over 10 levels. An arrow runs from a result to what uses it, and this result sits at the bottom with a heavier outline. Click the chart to enlarge it.

Sources