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False statementConstruction: Literature-sourcedVerification: AI-adaptedSession-authored (Fable 5 assisted)precheck passaudited 2026-08-21
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FALSE: continuity from above needs no finiteness hypothesis

Statement

False claim. For every decreasing sequence (Ek) of measurable sets, one has μ(kEk)=infkμ(Ek), without requiring any Ek to have finite measure. The valid theorem Continuity from above when one set has finite measure includes precisely that missing hypothesis.

Facts & Assumptions

Given: Counting measure # on N and the tails Ek:={nN:kn}.

[L1]

Counting measure assigns + to every infinite set (Counting measure on an arbitrary set) and is a measure (Counting measure is a measure).

[L2]

Continuity from above is proved when one member of the decreasing sequence has finite measure (Continuity from above when one set has finite measure).

[L3]

The natural order is defined by mn exactly when m+k=n for some natural k (Order on the natural numbers), natural addition is cancellative (Addition is cancellative), and k<k+1 (Discreteness: σ(n) is the immediate successor).

Refutation

technique · direct
1.1

The tails decrease, Ek+1Ek, and E0=N.

givenL3
1.2

Every Ek is infinite, because nk+n injects N into it; hence #(Ek)=+ for every k.

givenL1L3
1.3

The intersection is empty: if n belonged to every tail, it would belong to En+1, which would say n+1n, contrary to discreteness of the natural order.

givenL3
2.1

Thus #(kEk)=#()=0 but infk#(Ek)=+. This refutes the claim and shows why [L2] cannot be applied: no tail has finite counting measure.

step 1.2step 1.3L1L2

Depends on

Used by

Nothing in the library uses this result yet.

Dependency tree · two levels

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Sources