Alphabeta Math
LemmaStatement: Literature-sourcedProof: AI-adaptedSession-authored (Fable 5 assisted)precheck passjudge pass (openai/gpt-5.4)audited 2026-07-25
How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced — the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted — a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated — a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

Order is compatible with addition

Statement

For all m,n,kNm, n, k \in \mathbb{N}: mn    m+kn+km \le n \iff m + k \le n + k; and m<n    m+k<n+km < n \iff m + k < n + k (Order on the natural numbers).

Facts & Assumptions

Given: The order mn    j (m+j=n)m \le n \iff \exists j\ (m + j = n) (Order on the natural numbers) and addition with m+0=mm + 0 = m, m+σ(n)=σ(m+n)m + \sigma(n) = \sigma(m + n) (Addition of natural numbers).

[L1]

Addition is associative and commutative (Addition is associative, Addition is commutative).

[L2]

Cancellation: m+k=n+km=nm + k = n + k \Rightarrow m = n (Addition is cancellative).

Proof

technique · direct
1.1

Forward: if mnm \le n, say m+j=nm + j = n, then (m+k)+j=(m+j)+k=n+k(m + k) + j = (m + j) + k = n + k, so m+kn+km + k \le n + k.

givenL1
1.2

Backward: if m+kn+km + k \le n + k, say (m+k)+j=n+k(m + k) + j = n + k, then (m+j)+k=n+k(m + j) + k = n + k, so m+j=nm + j = n by cancellation, giving mnm \le n.

givenL1L2
2.1

The strict forms follow: m<nm < n means mnm \le n and mnm \ne n, while m+k=n+k    m=nm + k = n + k \iff m = n by cancellation, so m<n    m+k<n+km < n \iff m + k < n + k.

step 1.1step 1.2L2

Depends on

Used by

Dependency tree · next 3 levels

Direct dependencies and their dependencies through the next three levels: 18 results over 10 levels. An arrow runs from a result to what uses it, and this result sits at the bottom with a heavier outline. Click the chart to enlarge it.

Sources