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Nilpotent similarity is classified by the ranks of all powers

Statement

Let $N$ and $M$ be nilpotent endomorphisms of finite-dimensional vector spaces $V$ and $W$ over the same field $F$ , where similar means that some $F$ -linear isomorphism $φ : V \to W$ satisfies $M = φ N φ^{- 1}$ . Then $N$ and $M$ are similar if and only if $rank N^{k} = rank M^{k} for every k \geq 0.$ The $k = 0$ equality includes equality of the dimensions.

The common field is a hypothesis, not a convenience: rank sequences are integers and can agree across different fields, while similarity cannot. The zero endomorphisms of the one-dimensional spaces over $F_{2}$ and over $F_{3}$ have rank $1$ at $k = 0$ and rank $0$ for every $k \geq 1$ , and there is no linear isomorphism between them at all.

Facts & Assumptions

Given: Finite-dimensional nilpotent endomorphisms $N$ and $M$ over the same field.

[L1]

The ranks of all powers determine every nilpotent Jordan-block multiplicity (Power ranks determine every nilpotent Jordan-block multiplicity).

[L2]

Similarity is change of basis for one endomorphism and is an equivalence relation (Similarity is an equivalence relation, and two matrices represent the same endomorphism in two bases exactly when they are similar).

Proof

technique · direct

1.1L2algebra

If $N$ and $M$ are similar, conjugating $N^{k}$ gives $M^{k}$ ; an invertible change of coordinates preserves image dimension, so their ranks agree for every $k \geq 0$ .

1.2L1L2givenchoose

Conversely, equality of all power ranks makes the two Jordan-block multisets equal by [L1]. Choose Jordan-string bases $B$ of $V$ and $C$ of $W$ realising those multisets; since the multisets agree, both bases have the same length and $N$ and $M$ have the same block diagonal matrix in them. Because $V$ and $W$ are spaces over the same field $F$ , sending the $i$ th vector of $B$ to the $i$ th vector of $C$ defines an $F$ -linear isomorphism $φ : V \to W$ , and matching the block matrices entry by entry gives $φ N = M φ$ , hence $M = φ N φ^{- 1}$ ; [L2] identifies this with similarity.

2.1step 1.1step 1.2∎

Steps 1.1 and 1.2 establish both directions, with the empty block multiset covering zero-dimensional spaces.

Depends on

Used by

Nothing in the library uses this result yet.

Dependency tree · two levels

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Sources

S. Treil, Linear Algebra Done Wrong, Chapter 9, Sections 4.3-4.4 (standard reference, not scraped)