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Split characteristic polynomials decompose into generalised eigenspaces of the algebraic multiplicities
Statement
Let be an endomorphism of a finite-dimensional -vector space whose characteristic polynomial splits over . If is the exponent of in , then where ranges over the eigenvalues. Each is -invariant, is nilpotent of index , and Consequently is the algebraic multiplicity of in . For , the sum and eigenvalue set are empty.
Facts & Assumptions
Given: A finite-dimensional endomorphism whose characteristic polynomial splits over .
The minimal and characteristic polynomials have the same monic irreducible factors (The minimal and characteristic polynomials have exactly the same monic irreducible factors).
If splits with distinct and , then , and for every , (If the minimal polynomial splits, is the direct sum of the stabilised generalised eigenspaces).
Writing with the distinct monic irreducibles, the subspaces are -invariant, , and the minimal polynomial of is exactly (Primary decomposition: the irreducible-power factors of split into their invariant kernels).
Characteristic polynomials multiply across an invariant subspace and its quotient (For invariant , ).
For an endomorphism of a nonzero -dimensional space, nilpotency is equivalent to for some and to , and in that case is the nilpotency index (Characterisations of a nilpotent endomorphism).
Proof
Fact [L1] makes split over , so its distinct monic irreducible factors are the with an eigenvalue and . Fact [L2] gives the displayed invariant direct sum, and [L3] applied to the same factorisation gives that each has minimal polynomial exactly .
Fix an eigenvalue . Since is an eigenvalue, , and because ; hence is nonzero and [L5] applies to it. On , has minimal polynomial by step 1.1, so [L5] makes nilpotent of index and gives . Translating the scalar variable yields .
Repeated use of [L4] on the invariant direct sum multiplies these restricted characteristic polynomials to obtain , so the exponent is exactly the algebraic multiplicity. The empty product gives the zero-space case.
Depends on
- Primary components $\ker q(T)^e$ and generalised eigenspaces $G_\lambda^{(e)}(T)=\ker(T-\lambda I)^e$
- If the minimal polynomial splits, $V$ is the direct sum of the stabilised generalised eigenspaces
- The minimal and characteristic polynomials have exactly the same monic irreducible factors
- Primary decomposition: the irreducible-power factors of $\mu_T$ split $V$ into their invariant kernels
- Characterisations of a nilpotent endomorphism
- For invariant $W$, $\chi_T=\chi_{T|_W}\chi_{\bar T}$
Used by
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Sources
- S. Axler, Linear Algebra Done Right, 4th ed., Section 8A (standard reference, not scraped)