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Under Dependent Choice, nowhere differentiable functions form a residual subset of
Statement
Assume Dependent Choice. The nowhere differentiable functions form a residual subset of with the uniform metric, where differentiability at an endpoint means the corresponding one-sided derivative.
Facts & Assumptions
Given: The objects, hypotheses, and choice principles stated above.
Let be a topological space and let . The set is nowhere dense when (def-interior-closure-boundary-top). It is meagre when there is a sequence of nowhere dense subsets of with . It is residual, or comeagre, when is meagre. The empty union shows that is meagre, including when . (Nowhere dense, meagre, residual, and comeagre subsets of a topological space).
For , let be the functions for which some satisfies whenever and . Then is closed in the supremum metric. (Functions satisfying a fixed local Lipschitz bound somewhere form a closed subset of ).
For every , every , and every , there is a piecewise-affine with finitely many vertices such that and every slope on a nonvertex affine piece has absolute value greater than . (Polygonal functions with sufficiently steep nonvertex slopes are dense in ).
Proof
Fix positive integers . By the now choice-free proof of [F2], is closed. Given any uniform open ball, [F3] supplies within it a polygonal function whose slopes on all nonvertex pieces have absolute value greater than . At any , at least one side of contains arbitrarily close points on one such affine piece; the corresponding difference quotients have absolute value greater than . Hence . Every open ball meets the complement of , so has empty interior and is nowhere dense.
Enumerate the positive-integer pairs using [F4], and let . Step 1.1 and [F1] make a countable union of nowhere dense sets. If has a finite derivative at some (one-sided at an endpoint), the difference quotient is bounded near ; choose positive integers above that bound and so that is within the neighborhood. Then . Thus the complement of the set of nowhere differentiable functions is a subset of , and this same explicitly given countable family witnesses that the complement of is meagre. Hence is residual.
The preceding construction and implications establish the assertion.
Depends on
- Nowhere dense, meagre, residual, and comeagre subsets of a topological space
- Functions satisfying a fixed local Lipschitz bound somewhere form a closed subset of $C([0,1])$
- Polygonal functions with sufficiently steep nonvertex slopes are dense in $C([0,1])$
- $\mathbb{N} \times \mathbb{N} \approx \mathbb{N}$
Used by
Nothing in the library uses this result yet.
Dependency tree · two levels
38 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.
Sources
- David Marker, Descriptive Set Theory, §§1–2 (standard reference, not scraped)
- Michael Kunzinger, General Topology, §§11.3–11.4 (standard reference, not scraped)
- MFF General Topology course summary, §4.3 (standard reference, not scraped)