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CorollaryStatement: Literature-sourcedProof: AI-adaptedprecheck passverified 2026-09-23 (gpt-6-sol)
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Under Dependent Choice, nowhere differentiable functions form a residual subset of C([0,1],R)

Statement

Assume Dependent Choice. The nowhere differentiable functions form a residual subset of C([0,1],R) with the uniform metric, where differentiability at an endpoint means the corresponding one-sided derivative.

Facts & Assumptions

Given: The objects, hypotheses, and choice principles stated above.

[F1]

Let X be a topological space and let A⊆X. The set A is nowhere dense when int⁡(A‾)=∅ (def-interior-closure-boundary-top). It is meagre when there is a sequence (Nn)n∈N of nowhere dense subsets of X with A⊆⋃nNn. It is residual, or comeagre, when X∖A is meagre. The empty union shows that ∅ is meagre, including when X=∅. (Nowhere dense, meagre, residual, and comeagre subsets of a topological space).

[F2]

For p,q∈N>0, let Ep,q be the functions f∈C([0,1],R) for which some a∈[0,1] satisfies ∣f(t)−f(a)∣≤p∣t−a∣ whenever t∈[0,1] and ∣t−a∣<1/q. Then Ep,q is closed in the supremum metric. (Functions satisfying a fixed local Lipschitz bound somewhere form a closed subset of C([0,1])).

[F3]

For every f∈C([0,1],R), every ε>0, and every M>0, there is a piecewise-affine h with finitely many vertices such that ∥f−h∥∞<ε and every slope on a nonvertex affine piece has absolute value greater than M. (Polygonal functions with sufficiently steep nonvertex slopes are dense in C([0,1])).

[F4]

The pairs of natural numbers have a specified countable enumeration (N×N≈N).

Proof

technique · direct
1.1F2F3F1

Fix positive integers p,q. By the now choice-free proof of [F2], Ep,q is closed. Given any uniform open ball, [F3] supplies within it a polygonal function h whose slopes on all nonvertex pieces have absolute value greater than p. At any a∈[0,1], at least one side of a contains arbitrarily close points on one such affine piece; the corresponding difference quotients have absolute value greater than p. Hence h∉Ep,q. Every open ball meets the complement of Ep,q, so Ep,q has empty interior and is nowhere dense.

2.1step 1.1F1F2F4

Enumerate the positive-integer pairs (p,q) using [F4], and let M=⋃p,q≥1Ep,q. Step 1.1 and [F1] make M a countable union of nowhere dense sets. If f has a finite derivative at some a (one-sided at an endpoint), the difference quotient is bounded near a; choose positive integers p above that bound and q so that 1/q is within the neighborhood. Then f∈Ep,q. Thus the complement of the set N of nowhere differentiable functions is a subset of M, and this same explicitly given countable family witnesses that the complement of N is meagre. Hence N is residual.

3.1step 2.1∎

The preceding construction and implications establish the assertion.

Depends on

Used by

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