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One-dimensional Brownian motion hits every point almost surely

Statement

Assume the Axiom of Choice and let B be a standard Brownian motion Brownian motion. Use the everywhere-continuous, zero-start representative fixed in Distribution of a one-sided Brownian hitting time: replace the path by zero outside a measurable probability-one event of continuity and zero start, retaining the notation B. For aR, let τa=inf{t0:Bt=a}, with inf=+. Then each τa is a measurable [0,]-valued hitting time and P(τa<)=1 for every aR.

Facts & Assumptions

Given: AC, a standard Brownian motion B in the stated everywhere-continuous zero-start representative, and aR.

[F1]

For the representative in the statement and a>0, τa is a measurable extended random variable and, for t>0, P(τat)=2(1Φ(a/t)); the right side tends to 1 as t because Φ is continuous at 0 with Φ(0)=1/2. Distribution of a one-sided Brownian hitting time Standard normal and normal laws Cumulative distribution function of a real random variable

[F2]

Probability measures are continuous from below along increasing sequences of events. Basic identities for a probability measure

[F3]

If B is a standard Brownian motion then so is B: B0=0 almost surely, the increments change sign and centered normal laws are symmetric, and continuity is unchanged. Moreover τa(B)=τa(B) pathwise, because Bt=a if and only if Bt=a. Brownian motion

[F4]

The chosen representative satisfies B0=0 on every outcome, so τ0=0 everywhere. Distribution of a one-sided Brownian hitting time

[F5]

AC is the standing hypothesis under which the Brownian and hitting-time interfaces in [F1], [F3] and [F4] are supplied; no additional path is selected here. The Axiom of Choice

Proof

technique · direct
1.1

Let a>0. The events {τat} increase with t to {τa<}, so [F2] applied to the sequence t=n+1 gives P(τa<)=limnP(τan+1)=limn2(1Φ(a/n+1))=2(1Φ(0))=1 by [F1].

F1F2given
1.2

For a=0 the identity τ0=0 holds everywhere by [F4], so τ0 is measurable and P(τ0<)=1.

F4given
2.1

Let a<0. By [F3] the process B is a standard Brownian motion in an everywhere-continuous zero-start representative and τa(B)=τa(B) pathwise with a>0; [F1] makes the latter hitting time measurable, and step 1.1 applied to B and the level a gives P(τa(B)<)=P(τa(B)<)=1.

F1F3step 1.1
3.1

The cases a>0, a=0 and a<0 are exhaustive, so P(τa<)=1 for every real a. The conclusion concerns the first hitting time only; it does not assert finiteness of the expectation, and the case of a level already occupied at time 0 is contained in the a=0 case while for a0 the start B0=0 is a.s. distinct from a. AC is used only through [F5].

F5givenstep 1.1step 1.2step 2.1

Source notes

Durrett, Section 7.4, reads the almost-sure finiteness off the first-passage distribution at t; Sousi, Section 6.7, uses the same consequence for recurrence. The symmetry step is proved from the Brownian definition itself, so no separate invariance theorem for Wiener measure is assumed.

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