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CorollaryStatement: Literature-sourcedProof: AI-adaptedPipeline-generatedjudge pass (gpt-6.1-sol)
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The one-dimensional value depends on the characteristic interval

Statement

Let c>0 and let u be the solution of d'Alembert's formula and uniqueness in one dimension for data u0∈C2(R), u1∈C1(R). For every (x,t)∈R×[0,∞), the value u(x,t) is determined by the restrictions of u0 and u1 to the closed interval [x−ct,x+ct]: if (u~0,u~1) are admissible data agreeing with (u0,u1) there, then the corresponding solution satisfies u~(x,t)=u(x,t). In particular, changing the data outside [x−ct,x+ct] does not change the value at (x,t).

Facts & Assumptions

Given: a speed c>0, data u0∈C2(R), u1∈C1(R), a point (x,t)∈R×[0,∞), and admissible data (u~0,u~1) with u~0=u0 and u~1=u1 on [x−ct,x+ct].

[F1]

The d'Alembert formula of d'Alembert's formula and uniqueness in one dimension reads u(x,t)=12(u0(x−ct)+u0(x+ct))+12c∫x−ctx+ctu1(y) dy.

[F2]

The d'Alembert expression attains both initial data and defines the unique classical solution of the corresponding Cauchy problem (The d'Alembert expression attains both initial data, d'Alembert's formula and uniqueness in one dimension).

Proof

1.1F1algebra

The formula of [F1] evaluates u0 only at the two endpoints x−ct and x+ct of the interval and integrates u1 only over that interval; hence replacing (u0,u1) by any admissible pair with the same restrictions to [x−ct,x+ct] leaves the right-hand side unchanged, so the d'Alembert expression of the new data equals u(x,t) at the given point.

2.1F2algebra∎

By [F2] both expressions are the solutions of their respective Cauchy problems, so the solution u~ of the data (u~0,u~1) satisfies u~(x,t)=u(x,t); in particular the value at (x,t) is unchanged by altering the data off [x−ct,x+ct].

Depends on

Used by

Dependency tree · two levels

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Sources