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The d'Alembert expression attains both initial data
Statement
Let , , and let be the d'Alembert expression of d'Alembert's formula and uniqueness in one dimension, Then , for every , and so . The orientation of the velocity integral is the sign in the second bracket: both ends of the characteristic base are traversed with speed , and the two endpoint contributions add.
Facts & Assumptions
Given: a speed , data , , and the expression of the statement.
Let with and let be continuous on with continuous , where contains the closure of the union of the intervals . Then is with (Differentiating an integral with moving endpoints).
Sums, constant multiples of differentiable functions are differentiable with the usual rules (Sums, scalar multiples, products and quotients: , , , and when ).
If is totally differentiable at and at , then is totally differentiable at with (The chain rule for total derivatives: ). The required total differentiability follows from continuous coordinate partial derivatives (If all partial derivatives exist on a neighbourhood and are continuous at a point, then the map is totally differentiable there with Jacobian derivative).
Proof
Displacement at . At the two displacement terms are both and the integral has equal endpoints, so for every .
Velocity. For , by [F1] applied to the integral term with , , , and inner integrand , ; the displacement term is differentiated by [F2] and [F3]. Continuity of the data and the regularity supplied by d'Alembert's formula and uniqueness in one dimension extend this derivative formula to .
Setting in the velocity formula gives ; the regularity is established in d'Alembert's formula and uniqueness in one dimension. Hence attains both initial data, and the two endpoint contributions of the velocity integral add with a sign as displayed.
Depends on
- d'Alembert's formula and uniqueness in one dimension
- Differentiating an integral with moving endpoints
- Sums, scalar multiples, products and quotients: $(f+g)'(c) = f'(c) + g'(c)$, $(\alpha f)'(c) = \alpha f'(c)$, $(fg)'(c) = f'(c)g(c) + f(c)g'(c)$, and $(f/g)'(c) = \bigl(f'(c)g(c) - f(c)g'(c)\bigr)/g(c)^{2}$ when $g(c) \ne 0$
- The chain rule for total derivatives: $D(g\circ f)(a)=Dg(f(a))\circ Df(a)$
- If all partial derivatives exist on a neighbourhood and are continuous at a point, then the map is totally differentiable there with Jacobian derivative
Used by
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Sources
- Gerald Teschl, Partial Differential Equations: From Classical to Modern (2025 archived author manuscript, AMS Graduate Studies in Mathematics) (standard reference, not scraped)
- Victor Ivrii, Partial Differential Equations (University of Toronto, 2018, CC BY-SA) (standard reference, not scraped)
- Jared Speck, MIT 18.152 Introduction to Partial Differential Equations, Class Meeting #10: Introduction to the Wave Equation (Fall 2011) (standard reference, not scraped)