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The d'Alembert expression attains both initial data

Statement

Let c>0, u0∈C2(R), u1∈C1(R) and let A be the d'Alembert expression of d'Alembert's formula and uniqueness in one dimension, A(x,t):=12(u0(x−ct)+u0(x+ct))+12c∫x−ctx+ctu1(y) dy. Then A∈C2(R×[0,∞)), A(x,0)=u0(x) for every x, and ∂tA(x,t)=12(−cu0′(x−ct)+cu0′(x+ct))+12(u1(x+ct)+u1(x−ct)), so ∂tA(x,0)=u1(x). The orientation of the velocity integral is the + sign in the second bracket: both ends of the characteristic base are traversed with speed c, and the two endpoint contributions add.

Facts & Assumptions

Given: a speed c>0, data u0∈C2(R), u1∈C1(R), and the expression A of the statement.

[F1]

Let α,β∈C1(I) with α<β and let F be continuous on I×J with continuous ∂tF, where J contains the closure of the union of the intervals [α(t),β(t)]. Then G(t)=∫α(t)β(t)F(t,y) dy is C1 with G′(t)=F(t,β(t))β′(t)−F(t,α(t))α′(t)+∫α(t)β(t)∂tF(t,y) dy (Differentiating an integral with moving endpoints).

[F3]

If f is totally differentiable at a and g at f(a), then g∘f is totally differentiable at a with D(g∘f)(a)=Dg(f(a))∘Df(a) (The chain rule for total derivatives: D(g∘f)(a)=Dg(f(a))∘Df(a)). The required total differentiability follows from continuous coordinate partial derivatives (If all partial derivatives exist on a neighbourhood and are continuous at a point, then the map is totally differentiable there with Jacobian derivative).

Proof

1.1algebra

Displacement at t=0. At t=0 the two displacement terms are both u0(x) and the integral has equal endpoints, so A(x,0)=12(u0(x)+u0(x))+0=u0(x) for every x∈R.

1.2F1F2F3algebra

Velocity. For t>0, by [F1] applied to the integral term with α(t)=x−ct, β(t)=x+ct, α′(t)=−c, β′(t)=c and inner integrand u1, ∂tA(x,t)=12(−cu0′(x−ct)+cu0′(x+ct))+12c(c u1(x+ct)+c u1(x−ct))=12(−cu0′(x−ct)+cu0′(x+ct))+12(u1(x+ct)+u1(x−ct)); the displacement term is differentiated by [F2] and [F3]. Continuity of the data and the C2 regularity supplied by d'Alembert's formula and uniqueness in one dimension extend this derivative formula to t=0.

2.1F1algebra∎

Setting t=0 in the velocity formula gives ∂tA(x,0)=12(−cu0′(x)+cu0′(x))+12(u1(x)+u1(x))=u1(x); the regularity A∈C2(R×[0,∞)) is established in d'Alembert's formula and uniqueness in one dimension. Hence A attains both initial data, and the two endpoint contributions of the velocity integral add with a + sign as displayed.

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