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CorollaryStatement: Literature-sourcedProof: AI-generatedprecheck passjudge pass (gpt-5.6-terra)audited 2026-09-12
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Polynomial identity testing is in coRP

Statement

For every PIT representation that permits polynomial-time evaluation and polynomial-time construction of a finite sample set SF with Smax(1,2d), where d is the input's degree bound, the corresponding polynomial identity testing problem lies in coRP.

Facts & Assumptions

Given: a represented polynomial f in a PIT model with a computable degree bound d and a computable sample set S satisfying Smax(1,2d).

[L1]

RP and coRP are the one-sided-error probabilistic classes (The classes RP, coRP, ZPP, BPP, and PP).

[L2]

PIT asks whether the represented polynomial is identically zero, and the representation supports polynomial-time evaluation at chosen points (Polynomial identity testing).

[L3]

A nonzero polynomial of degree at most d vanishes on at most a d/S fraction of the points of Sn (The Schwartz-Zippel lemma).

Proof

technique · direct
1.1

On input the representation of f, compute its degree bound d, compute the sample set S, choose a uniformly random point of Sn, evaluate f at that point using [L2], and reject immediately if the value is nonzero; otherwise accept. The runtime is polynomial by the assumptions packaged into [L2].

L2givenconstruct
2.1

If f is the zero polynomial, every evaluation is zero, so the algorithm accepts with probability 1. If f is nonzero, [L3] gives P(f(a)=0)d/S1/2. So on no-instances the algorithm rejects with probability at least 1/2.

L3step 1.1algebra
3.1

Step 2.1 is exactly the coRP condition from [L1]. Therefore PIT is in coRP for every representation satisfying the stated assumptions.

L1step 2.1

Depends on

Used by

Dependency tree · two levels

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Sources