Alphabeta Math
CorollaryStatement: Literature-sourcedProof: AI-adaptedSession-authored (Fable 5 assisted)precheck passjudge pass (deepseek-v4-pro + gpt-5.6-terra)audited 2026-08-13
How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

Over a field of characteristic not 2, every quadratic form has diagonal coordinates q(x)=a1x12++anxn2

Statement

Let q be a quadratic form on an n-dimensional vector space over a field of characteristic not 2. Some basis gives

q(x1e1++xnen)=a1x12++anxn2

for scalars a1,,an, which may include zeros.

Facts & Assumptions

Given: The quadratic form q in the stated characteristic.

[L1]

Polarization gives a symmetric bilinear form Bq=12bq satisfying q(v)=Bq(v,v) (If charF2, quadratic forms and symmetric bilinear forms correspond by q(v)=B(v,v) and B(u,v)=12bq(u,v)).

[L2]

Every finite-dimensional symmetric bilinear form in characteristic not 2 has an orthogonal basis (Every symmetric bilinear form on a finite-dimensional space over a field of characteristic not 2 has an orthogonal basis).

Proof

technique · direct
1.1

Form Bq by [L1] and choose an orthogonal basis (e1,,en) by [L2]. Set ai=Bq(ei,ei).

L1L2choose
2.1

For v=ixiei, bilinearity and orthogonality give q(v)=Bq(v,v)=iaixi2; every cross term vanishes.

step 1.1L1algebra
3.1

This is the required diagonal expression. Zero coefficients are allowed, so degenerate forms and the zero form are included; for n=0 the sum is empty.

step 2.1

Depends on

Used by

Dependency tree · next 3 levels

Direct dependencies and their dependencies through the next three levels: 36 results over 12 levels. An arrow runs from a result to what uses it, and this result sits at the bottom with a heavier outline. Click the chart to enlarge it.

Sources