Alphabeta Math
CorollaryStatement: AI-adaptedProof: AI-adaptedprecheck passjudge pass (deepseek-v4-pro + gpt-5.6-terra)audited 2026-08-13
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The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

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Inside a common extension, the splitting field of fg is the composite of the splitting fields of f and g

Statement

Let f,g∈F[x] be nonzero. Inside a common field extension Ω/F, let Ef and Eg be their respective splitting fields. Then the composite EfEg inside Ω is a splitting field of fg over F.

Facts & Assumptions

Given: Nonzero f,g∈F[x] and splitting fields Ef,Eg⊆Ω.

[F1]

A splitting field is the subfield generated over F by all roots of the polynomial, over which that polynomial splits (Polynomials that split and splitting fields of a polynomial or a family of polynomials).

[F2]

The composite EfEg is the smallest subfield of Ω containing both Ef and Eg (The composite of two subfields is the subfield generated by their union).

Proof

technique · direct
1.1

Both f and g split over EfEg because the composite contains their splitting fields. Hence their product fg splits there.

F1F2
2.1

In the field Ω, an element a is a root of fg exactly when f(a)g(a)=0, hence exactly when it is a root of f or of g. Therefore the field generated by the roots of fg is the field generated jointly by Ef and Eg, which is EfEg by [F2].

F1F2algebra∎

Depends on

Used by

Dependency tree · two levels

5 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources