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CorollaryStatement: Literature-sourcedProof: AI-adaptedSession-authored (Fable 5 assisted)precheck passjudge pass (gpt-5.6-terra)audited 2026-08-28
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If k is algebraically closed and charkG, then i(dimkVi)2=G

Statement

Let G be a finite group and let k be an algebraically closed field with charkG. If V1,,Vr is a complete list of the irreducible representations of G over k, up to equivalence, then

i=1r(dimkVi)2=G.

Facts & Assumptions

Given: A finite group G and an algebraically closed field k with charkG.

[L1]

The regular representation decomposes as k[G]V1dimkV1VrdimkVr, where V1,,Vr are the irreducible representations of G (If k is algebraically closed and charkG, there are finitely many irreducible representations, and each occurs in the regular representation with multiplicity equal to its degree).

[L2]

For a finite group, dimkk[G]=G (If G is finite then dimkk[G]=G).

Proof

technique · direct
1.1

By [L1], the regular representation is a direct sum of dimkVi copies of each Vi, and [L2] says its total dimension is G.

L1L2given
2.1

Taking dimensions in step 1.1 gives G=dimkk[G]=i=1rdimk(VidimkVi)=i=1r(dimkVi)2. This is the required identity.

step 1.1givenalgebra

Depends on

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Dependency tree · two levels

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