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An extraspecial p-group of order p1+2n has generator rank 2n

Statement

Let P be an extraspecial p-group of order p1+2n. Then Φ(P)=Z(P) has order p, the Frattini quotient P/Φ(P) has order p2n, the generator rank is d(P)=2n, and every minimal generating set of P has exactly 2n elements.

Facts & Assumptions

Given: An extraspecial p-group P of order p1+2n.

[F1]

For a finite p-group P, the generator rank d(P) is the common size of a basis of P/Φ(P) (The generator rank d(P) of a finite p-group).

[F2]

A subset S of an elementary abelian p-group spans when every element is a product ∏s∈Ssas with coefficients in Fp, and is independent when such a product is the identity only for zero coefficients; a basis is an independent spanning subset (Fp-spanning sets, independence, and bases in an elementary abelian p-group).

[L1]

For a finite p-group P the following are equivalent: P is extraspecial; P is nonabelian, ∣Z(P)∣=p and P/Z(P) is elementary abelian; P is nonabelian and Z(P)=P′=Φ(P) has order p (Three equivalent descriptions of an extraspecial p-group).

[L2]

An extraspecial p-group has ∣P∣=p1+2n with n≥1 and ∣P/Z(P)∣=p2n (An extraspecial p-group has order p1+2n for some n≥1).

[L3]

Every finite elementary abelian p-group has a basis; every independent subset extends to a basis, every spanning subset contains a basis, and all bases have the same finite size (Finite elementary abelian p-groups have bases, basis extension, and a well-defined dimension).

[L4]

A subset X of a finite p-group P is a minimal generating set if and only if the quotient map restricts to a bijection from X onto a basis of P/Φ(P) (Burnside Basis Theorem).

[L5]

The rule aˉ⋅x=xa gives every elementary abelian p-group its canonical Fp-vector-space structure (An elementary abelian p-group has a canonical Fp-vector-space structure).

Proof

technique · direct
1.1L1

By the third description in the characterisation, Φ(P)=Z(P) has order p, so the Frattini quotient is the central quotient.

1.2L1L2

The central quotient has order p2n and is elementary abelian.

2.1F2L3L5step 1.1step 1.2

It therefore has a basis, and all of its bases have the same size, say k; independence and spanning make the map sending a coefficient family (a1,…,ak) to the product of the corresponding powers a bijection from the pk coefficient families onto the group, so pk=p2n and k=2n.

3.1F1L4step 2.1∎

Hence d(P)=2n by the definition of the generator rank, and by the Burnside basis theorem a minimal generating set of P is carried bijectively onto a basis of P/Φ(P), so it has 2n elements.

Remarks

The two clauses say different things. The first is about the quotient and is a count of a basis; the second is about P itself and needs the Burnside basis theorem, because a generating set of P of size 2n could a priori collapse in the quotient. It is the restricted-bijection clause of that theorem which rules that out.

Depends on

Used by

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Sources