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An automorphism of an extraspecial -group acting trivially on its Frattini quotient is inner
Statement
Let be an extraspecial -group of order and let be the induced-action homomorphism. Then : an automorphism of acting trivially on the Frattini quotient is inner.
Facts & Assumptions
Given: An extraspecial -group of order .
with (Inner automorphisms and ).
For a finite -group , the generator rank is the common size of a basis of (The generator rank of a finite -group).
is the intersection of the maximal proper subgroups of (The Frattini subgroup as the intersection of the maximal subgroups of a finite group).
An isomorphism is a bijective group homomorphism, and is the set of automorphisms of (Group isomorphisms, automorphisms and the set ).
For a finite -group the following are equivalent: is extraspecial; is nonabelian, and is elementary abelian; is nonabelian and has order (Three equivalent descriptions of an extraspecial -group).
An extraspecial -group has with and (An extraspecial -group has order for some ).
An extraspecial -group of order has of order and generator rank , and every minimal generating set has elements (An extraspecial -group of order has generator rank ).
Every automorphism of a finite -group induces an -linear automorphism of , and these form a homomorphism (Automorphisms act linearly on the Frattini quotient).
A subset of a finite -group is a minimal generating set if and only if the quotient map restricts to a bijection from onto a basis of (Burnside Basis Theorem).
If and are finite then is finite and (The product rule: , and ).
is the unique natural number with (The cardinality of a finite set).
Proof
The Frattini subgroup is of order , the Frattini quotient has order , and every minimal generating set of has exactly elements.
Fix a minimal generating set , which exists because the Burnside basis theorem matches minimal generating sets with bases of the Frattini quotient. An automorphism of is determined by its values on , since generates .
Every inner automorphism lies in : for one has , so fixes every coset of .
The inner automorphism group has order .
If lies in then for each , so with , a set of elements. Hence is determined by the tuple , and there are at most such tuples, so .
So is a subset of of size , while has at most elements; hence the two coincide.
Remarks
The equality is forced by two counts that happen to agree, and each uses the extraspecial hypothesis: the upper bound uses of order together with the generator rank , and the lower bound uses . For a general finite -group the kernel can be larger than the inner automorphism group; equality is not asserted or excluded without additional hypotheses.
Depends on
- Three equivalent descriptions of an extraspecial $p$-group
- An extraspecial $p$-group has order $p^{1+2n}$ for some $n\ge1$
- An extraspecial $p$-group of order $p^{1+2n}$ has generator rank $2n$
- Group isomorphisms, automorphisms and the set $\operatorname{Aut}(G)$
- Inner automorphisms and $\operatorname{Inn}(G)$
- $G/Z(G)\cong\operatorname{Inn}(G)$
- Automorphisms act linearly on the Frattini quotient
- Burnside Basis Theorem
- The generator rank $d(P)$ of a finite $p$-group
- The cardinality $\lvert A\rvert$ of a finite set
- The Frattini subgroup $\Phi(G)$ as the intersection of the maximal subgroups of a finite group
- The product rule: $\lvert A \times B\rvert = \lvert A\rvert\,\lvert B\rvert$, and $\big\lvert\prod_{i<m} A_i\big\rvert = \prod_{i<m}\lvert A_i\rvert$
- The center $Z(G)$ of a group
- Commutators $[g,h]=ghg^{-1}h^{-1}$ and the commutator subgroup $[G,G]$
Used by
Dependency tree · two levels
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Sources
- D. A. Craven, The Theory of p-Groups, Theorem 3.15(i) (standard reference, not scraped)