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PropositionStatement: Literature-sourcedProof: AI-adaptedSession-authored (Fable 5 assisted)precheck passaudited 2026-08-26
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An automorphism of an extraspecial p-group acting trivially on its Frattini quotient is inner

Statement

Let P be an extraspecial p-group of order p1+2n and let ρP:Aut(P)AutFp(P/Φ(P)) be the induced-action homomorphism. Then kerρP=Inn(P): an automorphism of P acting trivially on the Frattini quotient is inner.

Facts & Assumptions

Given: An extraspecial p-group P of order p1+2n.

[F1]

Inn(G):={cg:gG} with cg(x)=gxg1 (Inner automorphisms and Inn(G)).

[F2]

For a finite p-group P, the generator rank d(P) is the common size of a basis of P/Φ(P) (The generator rank d(P) of a finite p-group).

[F3]

Φ(G) is the intersection of the maximal proper subgroups of G (The Frattini subgroup Φ(G) as the intersection of the maximal subgroups of a finite group).

[F4]

An isomorphism is a bijective group homomorphism, and Aut(G) is the set of automorphisms of G (Group isomorphisms, automorphisms and the set Aut(G)).

[L1]

For a finite p-group P the following are equivalent: P is extraspecial; P is nonabelian, Z(P)=p and P/Z(P) is elementary abelian; P is nonabelian and Z(P)=P=Φ(P) has order p (Three equivalent descriptions of an extraspecial p-group).

[L2]

An extraspecial p-group has P=p1+2n with n1 and P/Z(P)=p2n (An extraspecial p-group has order p1+2n for some n1).

[L3]

An extraspecial p-group of order p1+2n has Φ(P)=Z(P) of order p and generator rank d(P)=2n, and every minimal generating set has 2n elements (An extraspecial p-group of order p1+2n has generator rank 2n).

[L4]

Every automorphism of a finite p-group induces an Fp-linear automorphism of P/Φ(P), and these form a homomorphism ρP (Automorphisms act linearly on the Frattini quotient).

[L5]

A subset X of a finite p-group P is a minimal generating set if and only if the quotient map restricts to a bijection from X onto a basis of P/Φ(P) (Burnside Basis Theorem).

[L6]

G/Z(G)Inn(G) (G/Z(G)Inn(G)).

[L7]

If A and B are finite then A×B is finite and A×B=AB (The product rule: A×B=AB, and i<mAi=i<mAi).

[L8]

A is the unique natural number n with An (The cardinality A of a finite set).

Proof

technique · direct
1.1

The Frattini subgroup is Φ(P)=Z(P) of order p, the Frattini quotient has order p2n, and every minimal generating set of P has exactly 2n elements.

F2F3L1L2L3
2.1

Fix a minimal generating set X={g1,,g2n}, which exists because the Burnside basis theorem matches minimal generating sets with bases of the Frattini quotient. An automorphism of P is determined by its values on X, since X generates P.

F4L5step 1.1
2.2

Every inner automorphism lies in kerρP: for g,xP one has cg(x)x1=gxg1x1[P,P]=Φ(P), so cg fixes every coset of Φ(P).

F1L1L4step 1.1
2.3

The inner automorphism group has order P/Z(P)=p2n.

F1L2L6step 1.1
3.1

If θ lies in kerρP then θ(gi)Φ(P)=giΦ(P) for each i, so θ(gi)=giui with uiΦ(P)=Z(P), a set of p elements. Hence θ is determined by the tuple (u1,,u2n), and there are at most p2n such tuples, so kerρPp2n.

F3L4L7L8step 1.1step 2.1
4.1

So Inn(P) is a subset of kerρP of size p2n, while kerρP has at most p2n elements; hence the two coincide.

L8step 3.1step 2.2step 2.3

Remarks

The equality is forced by two counts that happen to agree, and each uses the extraspecial hypothesis: the upper bound uses Φ(P)=Z(P) of order p together with the generator rank 2n, and the lower bound uses P/Z(P)=p2n. For a general finite p-group the kernel can be larger than the inner automorphism group; equality is not asserted or excluded without additional hypotheses.

Depends on

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Sources