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LemmaStatement: Literature-sourcedProof: AI-adaptedprecheck passjudge pass (deepseek-v4-pro + claude-opus-5[1m])audited 2026-08-24
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  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

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An elementary abelian p-group has a canonical Fp-vector-space structure

Statement

The rule aˉ⋅x=xa gives every elementary abelian p-group its canonical Fp-vector-space structure, with the group operation as vector addition and the identity as zero.

Facts & Assumptions

Given: An elementary abelian p-group E, a residue class aˉ∈Z/p, and x,y∈E, with integer powers as in Powers gn: natural exponents in a monoid and integer exponents in a group, with g0=e.

[F1]

An elementary abelian p-group is a finite abelian p-group in which every nonidentity element has order p; the trivial group is permitted (Elementary abelian p-groups).

[L1]

For every prime p, addition and multiplication make Z/p a field (For every prime p, the two operations on Z/p make it a field).

[L2]

The additive structure of Z/p is an abelian group and multiplication distributes over addition (For every natural n, (Z/n,+) is an abelian group, multiplication is a commutative monoid operation, and both distributive laws hold).

[L3]

For integers a,b, one has xa+b=xaxb and (xa)b=xab; if xy=yx, then (xy)a=xaya (Exponent laws in a group: gm+n=gmgn and (gm)n=gmn for all m,n∈Z, and (gh)n=gnhn when g and h commute).

Proof

technique · direct
1.1givenF1L2L3algebra

If a≡b(modp), then a−b=kp for an integer k. Since xp=e by [F1], the power laws in [L3] give xa=xb(xp)k=xb. Thus aˉ⋅x:=xa is independent of the representative.

2.1step 1.1F1L1L2L3algebra

The power laws in [L3] and commutativity give (aˉ+bˉ)⋅x=(aˉ⋅x)(bˉ⋅x), (aˉbˉ)⋅x=aˉ⋅(bˉ⋅x), aˉ⋅(xy)=(aˉ⋅x)(aˉ⋅y), 1ˉ⋅x=x, and 0ˉ⋅x=e. Together with [L1] and [L2], these are the vector-space axioms.

3.1step 2.1F1L1algebra∎

The scalar structure uses the existing abelian group law and does not change its elements. In particular its additive group remains finite, abelian, and of exponent p, including the zero-dimensional trivial case.

Depends on

Used by

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Sources