Alphabeta Math
CorollaryStatement: Literature-sourcedProof: AI-adaptedprecheck passaudited 2026-08-13
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Every 1+u with u∈xR⟦x⟧ has a unique kth root with constant coefficient 1 in a commutative Q-algebra

Statement

Let R be a commutative Q-algebra, u∈xR⟦x⟧, and k≥1. There is a unique v∈1+xR⟦x⟧ such that

vk=1+u,

namely v=(1+u)1/k. When u=0, this unique root is 1.

Facts & Assumptions

Given: The hypotheses and notation of the statement above.

[F1]

In a commutative Q-algebra, formal exp⁡ and log⁡ are inverse group homomorphisms on xR⟦x⟧ and 1+xR⟦x⟧, and for u∈xR⟦x⟧ and c,d∈R the exponent-addition and exponent-multiplication laws hold (Formal exp⁡ and log⁡ are inverse homomorphisms and formal binomial powers obey the expected addition laws).

Proof

technique · apply the formal logarithm
1.1

The power law gives ((1+u)1/k)k=(1+u)1=1+u, so the stated series is a root with constant coefficient 1.

givenF1
1.2

If v∈1+xR⟦x⟧ and vk=1+u, the logarithm addition law gives klog⁡v=log⁡(1+u). Since k is invertible in a Q-algebra, log⁡v=(1/k)log⁡(1+u); applying exp⁡ gives v=(1+u)1/k. This proves uniqueness.

givenF1
2.1

For u=0, the construction is exp⁡(0)=1, and step 1.2 excludes any other constant-one root.

step 1.1step 1.2givenF1∎

Depends on

Used by

Dependency tree · two levels

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Sources