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W2,p regularity implies classical or H"older regularity when p is large

Statement

Assume the Axiom of Choice. Let n≥2, 1<p<∞, and let Ω be a bounded W2,p-extension domain (the extension property is for this displayed k=2 and exponent p). (i) If p>n/2, every u∈W2,p(Ω) has a representative in C0,γ(Ωˉ) for every 0<γ<min⁡{1,2−n/p}, with the norm controlled by ∥u∥W2,p. (ii) If p>n, every such u has a representative in C1,γ(Ωˉ) for every 0<γ<1−n/p, with the corresponding norm bound; in particular D2u∈Lp. For any nondivergence expression Lu=∑∣β∣≤2aβDβu with aβ∈L∞(Ω), this gives Lu∈Lp(Ω); whenever Lu=f also holds distributionally for some f∈Lp(Ω), the equality then holds almost everywhere. (iii) If p>n/(1−α) for 0<α<1, the representative is C1,α(Ωˉ). No finite p gives C2,α regularity in general: on a ball, the function u(x)=(x1)+2 belongs to W2,p for every finite p, while D11u=21{x1>0} has no continuous representative.

Facts & Assumptions

Given: the Axiom of Choice, n≥2, 1<p<∞, the bounded W2,p-extension domain Ω, and u∈W2,p(Ω).

[A1]

The Axiom of Choice is the standing hypothesis, used through the extension operator and the embedding theorem below. (The Axiom of Choice)

[F1]

By the extension property there is a bounded linear E:W2,p(Ω)→W2,p(Rn) with (Eu)∣Ω=u almost everywhere and ∥Eu∥W2,p(Rn)≤CE∥u∥W2,p(Ω). (Sobolev extension domains and extension operators)

[F2]

Higher-order Sobolev embedding (Higher-order Sobolev embedding): for a bounded extension domain and k≥1, 1≤q<∞, (a) if kq<n then Wk,q↪Lr for every 1≤r≤nq/(n−kq); (b) if kq=n then Wk,q↪Lr for every finite r; (c) if kq>n then every u∈Wk,q has a representative in Cm,β(Ωˉ) for every integer m≥0 and 0<β<1 with m+β<k−n/q, with the norm bounded by a constant times ∥u∥Wk,q. Applied with k=2 and q=p, the three cases are 2p<n, 2p=n, 2p>n; the case 2p>n is exactly p>n/2. (Higher-order Sobolev embedding)

[F3]

The witness on the unit ball Ω=B(0,1): for u(x)=(x1)+2:=max⁡{x1,0}2, the weak derivatives are ∂1u=2(x1)+, ∂11u=21{x1>0} and ∂iju=0 otherwise. Thus u∈W2,p(Ω) for every finite p. On the disk section Ω∩{x1=0} the one-sided values of ∂11u differ, so this weak derivative has no continuous representative; consequently u∉C2,α(Ωˉ) for every 0<α<1. (Integer-order Sobolev spaces and their norms)

[F4]

The unit ball is a bounded C2 domain and hence a W2,p-extension domain for every 1≤p≤∞ (Bounded C^k domains and boundary charts, Bounded C^k domains admit integer-order Sobolev extension).

[F5]

If two locally integrable functions represent the same distribution on Ω, they agree almost everywhere; this is the uniqueness of the zeroth weak derivative (Uniqueness of a weak derivative as an almost-everywhere class).

Proof

technique · direct application of the bounded-domain embedding
1.1F1F2givenA1

Domain hypothesis. By the definition of a W2,p-extension domain [F1], Ω satisfies the bounded-domain premise of [F2] for k=2 and exponent p. The embedding conclusion of [F2] is already on Ωˉ; no embedding on the unbounded space Rn is used.

1.2F3F4givenalgebra

The ball witness: no finite p gives C2,α. On Ω=B(0,1) let u(x)=max⁡{x1,0}2. The function is C1 with ∂1u=2max⁡{x1,0}, and integration by parts on the two sides of x1=0 gives the weak derivative ∂11u=21{x1>0}; the interface term vanishes because max⁡{x1,0} is continuous there. All second derivatives are bounded, so u∈W2,p(Ω) for every finite p. If ∂11u had a continuous representative, it would equal 0 on the negative open half-ball and 2 on the positive open half-ball: the almost-everywhere equalities force these values on each open side by continuity. They cannot extend continuously across the interior disk Ω∩{x1=0}. Thus u has no C2,α representative for any 0<α<1. The ball is in the stated extension-domain class by [F4].

2.1step 1.1F2algebra

Part (i): p>n/2. Then 2p>n. For every 0<γ<min⁡{1,2−n/p} the embedding [F2] with k=2, q=p, m=0 gives a representative u∗∈C0,γ(Ωˉ) and ∥u∗∥C0,γ(Ωˉ)≤C∥u∥W2,p(Ω). If 2−n/p≥1, the same strict inequality allows every 0<γ<1.

2.2step 1.1F2F5algebra

Part (ii): p>n. Then 2−n/p>1. For each 0<γ<1−n/p, one has 1+γ<2−n/p, so [F2] with k=2, q=p, m=1 gives a representative u∗∈C1,γ(Ωˉ) and the stated norm bound. The weak derivatives Dβu with ∣β∣≤2 are Lp classes by the definition of W2,p. Thus for L=∑∣β∣≤2aβDβ with bounded coefficients, Lu is an Lp class. If also Lu=f distributionally with f∈Lp, then [F5] gives equality of the represented classes almost everywhere.

2.3step 1.1F2algebra

Part (iii): p>n/(1−α). Then 1+α<2−n/p, so [F2] with k=2, q=p, m=1 and exponent α gives a representative in C1,α(Ωˉ) with norm bounded by C∥u∥W2,p(Ω). Parts (i), (ii), (iii) are direct applications of the bounded-domain higher-order embedding.

3.1step 2.1step 2.2step 2.3step 1.2F2∎

Conclusion. The higher-order embedding gives the asserted C0,γ representatives when p>n/2, C1,γ representatives when p>n, and C1,α representatives when p>n/(1−α). The ball witness of step 1.2 shows that no finite p forces C2,α regularity in general, so the Sobolev and Schauder scales differ at the top order.

Remarks

  • The hypothesis is indexed by (k,p)=(2,p): a domain that is an extension domain for one pair need not be for another, and the statement uses only the displayed pair. The counterexample on the ball shows that the extension property alone, or any finite p, cannot produce two H"older derivatives.
  • The strict exponent ranges in the statement are sufficient, rather than an assertion of optimality. For p>n, the endpoint clause of Higher-order Sobolev embedding also gives C1,1−n/p(Ωˉ), since 2−n/p∈(1,2) is nonintegral; for example p=2n gives C1,1/2. The ball witness shows that no finite p forces two Hölder derivatives.

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