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Chords of a labelled convex polygon, crossing, and triangulations, defined combinatorially
Definition
Let with , and write the vertices of a labelled convex -gon as the cyclically ordered set .
A chord is a two-element subset with . It is a side when or , and a diagonal otherwise.
Two chords and cross when
This is a condition on the cyclic order of the labels alone; no segment and no area enters the definition.
A triangulation of the labelled -gon is a set of diagonals such that
- no two members of cross; and
- is maximal with that property.
Write for the set of triangulations of the labelled -gon.
For and there are no diagonals at all, so the empty set is the unique triangulation:
For every fixed the set of diagonals is finite, being a subset of the finite set of all chords, so is a finite set of finite sets (A subset of a finite set is finite, with , and equality holds if and only if , The cardinality of a finite set).
Remarks
-
The word "convex" in the title is only the picture attached to the cyclic order on the labels. The development below uses only the combinatorial crossing relation written above.
-
The side is singled out often enough to deserve a name: it is the closing side. The splitting lemma below decomposes a triangulation along the unique triangle touching that side.
Depends on
Used by
- A map from hexagon triangulations to size-four binary trees that is not injective Counterexample
- All fourteen triangulations of the labelled hexagon Example
- The five Dyck paths, balanced bracket words, binary trees and pentagon triangulations at semilength 3 Example
- For m≥3 and a triangulation T of the m-gon there is a unique k with 1<k<m such that {1,k} and {k,m} are both chords of T or sides, and T splits along k Lemma
- The trees and polygons of this page are defined by recursion and by inequalities on labels Remark
- There is a bijection Tₙ toPₙ₊₂ for every n∈ℕ Theorem
Dependency tree · two levels
20 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.
Sources
- D. Guichard, An Introduction to Combinatorics and Graph Theory, §3.5 (standard reference, not scraped)