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DefinitionDefinition: Literature-sourcedProof: Not applicablePipeline-generatedjudge pass (gpt-6.1-sol)audited 2026-10-08
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The normalized type-A Hecke algebra and its bar involution

Definition

Let n≥1 and A:=Z[v±1]. For n≥2, define the normalized type-A Hecke algebra Hv(n) to be the associative unital A-algebra presented by generators Hs1,…,Hsn−1 with relations Hsi2=1+(v−1−v)Hsi,HsiHsi+1Hsi=Hsi+1HsiHsi+1,HsiHsj=HsjHsi(∣i−j∣>1). For n=1, set Hv(1):=A.

Here Sn=Sym⁡({1,…,n}), si=(i i+1), and ℓ is inversion length as in The symmetric group Sym⁡(X): the bijections of a set X under composition and Permutation Weyl group and inversion length. For w∈Sn, let Tw be the standard basis element of the generic Hecke algebra of The generic type-A Hecke algebra, formed from any reduced expression of w, and after the coefficient specialization q↦v−2 put Hw:=vℓ(w)Tw. Equivalently, Hw=Hsi1⋯Hsik for a reduced expression w=si1⋯sik. The standard-basis theorem The standard basis of the generic type-A Hecke algebra and rescaling by units show that {Hw:w∈Sn} is an A-basis of Hv(n).

Right multiplication by a generator is HwHsi=Hwsiif ℓ(wsi)=ℓ(w)+1,HwHsi=Hwsi+(v−1−v)Hwif ℓ(wsi)=ℓ(w)−1.

Dictionary with the generic normalization. If the generic parameter in The generic type-A Hecke algebra is denoted by q, its relation is Ti2=(q−1)Ti+q. The coefficient map q↦v−2 is the stated specialization, and Hsi=vTi. This gives Hsi2=1+(v−1−v)Hsi; the braid and commutation relations are unchanged. The two multiplication cases above are the standard-basis rule after the same rescaling.

Bar assignment. Let F be the free associative Z[v±1]-algebra on the generator symbols. Define the semilinear algebra map ι0:F→F by ι0(v)=v−1 and ι0(Hsi)=Hsi−(v−1−v). In the quotient Hv(n), the quadratic relation makes this latter element the two-sided inverse Hsi−1. The next lemma proves that ι0 preserves the defining ideal and descends to a well-defined involution ι on Hv(n).

All items on this page use this normalization. It agrees with Elias–Williamson §3.2 under Hx=vℓ(x)Tx and q=v−2.

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