Alphabeta Math
LemmaStatement: Literature-sourcedProof: AI-adaptedPipeline-generatedprecheck passaudited 2026-10-08
How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

Star operations are Knuth moves and preserve the relevant cells

Facts & Assumptions

Given: n≥3, 1≤i≤n−2, r=si, t=si+1, WI=⟨r,t⟩≅S3, and the corresponding right star operation.

[F1]

Each right coset of WI has a unique shortest representative w~; its six elements have lengths ℓ(w~)+0,ℓ(w~)+1,ℓ(w~)+1,ℓ(w~)+2,ℓ(w~)+2,ℓ(w~)+3, and the star involution pairs w~r↔w~rt and w~t↔w~tr. In one-line notation these pairs are bac↔bca and acb↔cab (Star operations on strings of adjacent simple reflections).

[F2]

A Knuth move preserves the insertion tableau, and Knuth equivalence is exactly equality of insertion tableaux (Knuth classes are the fibers of the insertion tableau).

[F3]

For a simple reflection s, if sw>w then CsCw=Csw+∑z:sz<z<wμ(z,w)Cz, and if sw<w then CsCw=(v+v−1)Cw; on the right, if ws>w then CwCs=Cws+∑zs<z<wμ(z,w)Cz, and if ws<w then CwCs=(v+v−1)Cw (Multiplication by a generator in the Kazhdan–Lusztig basis).

[F4]

A right coefficient step is a right preorder step, and x∼Ry iff x−1∼Ly−1 (L-, R- and two-sided Kazhdan–Lusztig preorders and cells).

[F5]

In Cw=∑x≤wpx,wHx, the coefficients are supported on x≤w and pw,w=1; if x⋖w is a Bruhat cover, then px,w=v (Existence and uniqueness of the Kazhdan–Lusztig basis). The latter follows from the degree-one leading term and parity clauses.

[F6]

For x≤y, px,y=vℓ(y)−ℓ(x)Px,y(v−2), and for x<y, μ(x,y) is the coefficient of v in px,y (Kazhdan–Lusztig polynomials in the classical q-normalization).

[F7]

The standard Hecke basis satisfies Hs2=1+(v−1−v)Hs (The normalized type-A Hecke algebra and its bar involution).

[F8]

Bruhat order on Sn has the reduced-subword characterization and is graded by inversion length (Basic properties of the Bruhat order on Sn).

Statement

Let Di and (−)∗ be as in Star operations on strings of adjacent simple reflections. (a) For w∈Di, w∗ is obtained from w by one elementary Knuth relation on the letters in positions i,i+1,i+2; in particular P(w∗)=P(w). Put Dij:={w∈Di:wsi<w, wsi+1>w} and Dji:={w∈Di:wsi>w, wsi+1<w}. The restriction Kij of (−)∗ is a bijection Dij→Dji whose inverse is Kji. (b) For every w∈Di, if a and b are the shorter and longer, respectively, of {w,w∗}, then μ(a,b)=1 and w∗∼Rw; by inversion, ∗w∼Lw whenever w−1∈Di. (c) Inside the rank-two subgroup WI=⟨si,si+1⟩≅S3, every Kazhdan–Lusztig polynomial Px,y with x≤y is 1, and μ(x,y)=1 exactly for Bruhat covers x⋖y. For every shortest representative w~ of a right WI-coset, the ambient pairs w~si⋖w~sisi+1 and w~si+1⋖w~si+1si therefore also have μ-coefficient 1.

Proof

technique · use the explicit $S_3$ star table, compute its rank-two Kazhdan–Lusztig basis, and apply the left/right multiplication formulas to the two directed edges of each star pair
1.1F1F2

Knuth moves and the restricted bijection. In the sorted-coset notation of [F1], the four elements of Di have local triples bac,bca,acb,cab, and the star table exchanges bac↔bca and acb↔cab. These are exactly the two elementary Knuth moves, so [F2] gives P(w∗)=P(w). The right descent of each pair is exchanged between si and si+1; hence (−)∗ maps Dij to Dji. Since (−)∗ is an involution, its restriction is a bijection with inverse Kji.

1.2F3F5F6F7F8algebra

The rank-two basis and coefficients. Write e for the identity and w0=rtr=trt. The six elements of WI are e,r,t,rt,tr,w0, and their Bruhat intervals follow from reduced subwords. Since e⋖r,t, the support and diagonal clauses of [F5] give Cr=Hr+v and Ct=Ht+v. For CrCt, the left multiplication formula has no correction term: [e,t]={e,t} and re=r>e. Similarly, CtCr has no correction term because [e,r]={e,r} and te=t>e. Thus Crt=CrCt and Ctr=CtCr; expanding with [F7] gives Crt=Hrt+v(Hr+Ht)+v2He and Ctr=Htr+v(Hr+Ht)+v2He. The interval [e,tr) consists of e,t,r, and only r satisfies rz<z there; since r⋖tr, [F5]–[F6] give μ(r,tr)=1. Thus Cw0=CrCtr−Cr=Hw0+v(Hrt+Htr)+v2(Hr+Ht)+v3He. Comparing these six expansions with px,y=vℓ(y)−ℓ(x)Px,y(v−2) shows Px,y=1 for every x≤y in WI. For such pairs the coefficient of v in px,y=vℓ(y)−ℓ(x) is 1 exactly when the length difference is 1, i.e. exactly on covers.

1.3F1F5F6F8

Ambient star-pair coefficients. The lengths in [F1] show that each of w~r⋖w~rt and w~t⋖w~tr is an ambient Bruhat cover: the upper element is the lower element multiplied on the right by one simple reflection and its length increases by one. Thus [F5]–[F6] give μ(w~r,w~rt)=μ(w~t,w~tr)=1. These are precisely the shorter-to-longer star-pair coefficients, so the Statement's coefficient claim holds for either choice of w.

2.1F1F3F4step 1.3

Right-cell equivalence. Since the claim is symmetric in the star pair, take its shorter member w. By [F1], either w=w~r and w∗=wt=w~rt, or w=w~t and w∗=wr=w~tr. In the first case [F3] gives a coefficient-1 right step from w to w∗; also w∗r=w~rtr has length ℓ(w~)+3, whereas wr=w~, so the right-ascent formula for Cw∗Cr contains Cw with coefficient μ(w,w∗)=1 by step 1.3. In the second case the coefficient-1 step comes from CwCr, and w∗t=w~trt has length ℓ(w~)+3 while wt=w~, so Cw∗Ct contains Cw with coefficient μ(w,w∗)=1. Each case therefore gives both w∗≤Rw and w≤Rw∗, proving w∗∼Rw.

3.1F1F4step 2.1∎

The dual statement. For w−1∈Di, step 2.1 gives (w−1)∗∼Rw−1. Inverting this equivalence by [F4] yields ∗w=((w−1)∗)−1∼Lw.

Remarks

The original scaffold's proposed identity Cw~u=∑t≤uvℓ(u)−ℓ(t)Hw~t for an arbitrary shortest right-coset representative is false: with n=4, WI=⟨s1,s2⟩, w~=s3, and u=s2, the left side is Hs3s2+vHs3+vHs2+v2He, whereas the displayed coset sum omits vHs2+v2He. The rank-two claim is stated for the subgroup itself, and the ambient star-pair coefficients follow separately from the cover property.

The star-pair and cell arguments use the locally proved multiplication formula, cover coefficient and inversion-of-cells clauses. Coefficientwise positivity is not required. No Choice is used.

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