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DefinitionDefinition: Literature-sourcedProof: AI-adaptedPipeline-generatedprecheck passaudited 2026-09-30
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Order and lower order from the Nevanlinna characteristic

Statement

Let f be nonconstant meromorphic on C. Its characteristic is nondecreasing, and T(r,f)>1 for all sufficiently large r. Define its order and lower order by ρ(f)=lim sup⁡r→∞log⁡T(r,f)log⁡r,λ(f)=lim inf⁡r→∞log⁡T(r,f)log⁡r, using only sufficiently large r>1 with T(r,f)>1. Both values lie in [0,∞]; f has finite order when ρ(f)<∞. For every constant finite map, set ρ(f)=λ(f)=0 by convention. For entire functions, the next proposition compares this order with the classical maximum-modulus order; meromorphic growth is measured by T, which remains finite in the presence of poles.

Facts & Assumptions

Given: The characteristic, integrated counts, and normalized chordal proximity for a meromorphic function on C.

[F1]

The integrated count is N(r,a;f)=n(0,a;f)log⁡r+∫0r(n(t,a;f)−n(0,a;f)) dt/t (Counting, chordal proximity and characteristic).

[F2]

The characteristic is T(r,f)=m(r,∞;f)+N(r,∞;f) (Counting, chordal proximity and characteristic).

[F3]

The normalized chordal sphere has diameter one, so log⁡(1/δ(f,a))≥0 and every proximity is nonnegative (Counting, chordal proximity and characteristic).

[F4]

The First Main Theorem gives m(r,a;f)+N(r,a;f)=T(r,f)+C(f,a) with a fixed finite centre constant (Nevanlinna’s First Main Theorem with exact centre constant).

[F5]

The Ahlfors–Shimizu identity is T(r,f)=TAS(r,f)+C∞(f), and TAS is finite and nondecreasing (Ahlfors–Shimizu area form of the characteristic).

Proof

technique · use a central divisor to force logarithmic growth of $T$, then use the area identity to establish monotonicity of the characteristic
1.1F1algebra

For any target a, n(t,a;f)≥n(0,a;f), so [F1] gives N(r,a;f)≥n(0,a;f)log⁡r for r>1.

2.1F2F3F4step 1.1algebra

If f(0) is finite, take a=f(0); then n(0,a;f)≥1 and [F4], [F3], and step 1.1 give T(r,f)≥log⁡r−C(f,a). If 0 is a pole, then n(0,∞;f)≥1 and [F2], [F3], and step 1.1 give T(r,f)≥log⁡r. Thus T(r,f)→∞ and is greater than 1 for all sufficiently large r.

3.1F5step 2.1algebra∎

By [F5], T is nondecreasing; by step 2.1 the logarithmic ratio in the statement is defined and nonnegative for all sufficiently large r. Its limsup and liminf therefore lie in [0,∞].

Depends on

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Sources