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The reduced Burau representation

Definition

Assume AC (inherited from the lift of braid mapping classes). Let Mred be the reduced Burau module over Λ1=Z[t±1], free of rank n−1. Write hi=[ϵi−ϵn] for the transported basis of The reduced Burau module is free of rank n minus one, and put hn=0. For the matrix representation fix the adjacent weighted basis bi:=ti(hi−hi+1)=[ti(ϵi−ϵi+1)],1≤i≤n−1. It is a basis because hi=∑k=in−1t−kbk; these formulas are inverse changes of coordinates. For n=1 both bases are empty. Let h~ be the basepoint-normalised lift of a representative homeomorphism of β∈Bn constructed in Braid mapping classes lift equivariantly to the Burau cover. The reduced Burau representation is ρˉn:Bn⟶GL⁡n−1(Λ1),β⟼the matrix of (h~)∗ on Mred in the fixed basis.

It is well defined because a different representative is isotopic and its lift acts by the same Λ1-module automorphism, and because the matrix is taken in the basis (b1,…,bn−1); it is a homomorphism because the induced homology action is a homomorphism; and it is Λ1-linear because the lift commutes with the deck group. Conventions: matrices act on column vectors, with the basis (bi) in increasing index order. The original basis (hi) gives conjugate matrices.

Facts & Assumptions

Given: AC; the identification Bn≅Mod⁡(D2,Qn;∂D2) of Braid group as boundary-fixed punctured-disk mapping classes, The Artin presentation is complete for geometric braids; the reduced Burau module Mred with its fixed Λ1-basis; and a braid β∈Bn.

[F1]

For every braid class there is a homeomorphism representative; the basepoint-normalised lifts of isotopic representatives are isotopic as maps of pairs and therefore induce equal homology maps; these induced maps form a homomorphism from Bn, and each h~ acts on Mred by a Λ1-module automorphism (Braid mapping classes lift equivariantly to the Burau cover, Braid group as boundary-fixed punctured-disk mapping classes, The Artin presentation is complete for geometric braids).

[F2]

Mred is free of rank n−1 over Λ1 with basis (hi); the inverse coordinate formulas in the definition give the fixed basis (bi). The matrix of a Λ1-module endomorphism in a fixed basis is invertible exactly when the endomorphism is an automorphism; matrices compose under the library convention that the leftmost factor is applied last (The reduced Burau module is free of rank n minus one, Invertible square matrices and similarity over a commutative ring, The Laurent polynomial ring as the principal localisation of Z[t] at t).

Proof

technique · direct
1.1F1F2

Well-definedness. Choose a representative homeomorphism h of the mapping class of β; any two such representatives are isotopic through boundary-fixed homeomorphisms preserving Qn setwise, so by [F1] their basepoint-normalised lifts have the same action on Mred. Hence the Λ1-module automorphism (h~)∗ depends only on β; its matrix in the fixed basis therefore depends only on β.

1.2F1F2

Homomorphism property. If h1,h2 represent β1,β2, then h1h2~=h~1∘h~2 by [F1], so (h1h2~)∗=(h~1)∗∘(h~2)∗ and, in the fixed basis, the matrix of the composite is the product of the matrices in the library composition order of [F2]. Thus ρˉn(β1β2)=ρˉn(β1)ρˉn(β2).

2.1F1F2step 1.1step 1.2∎

Λ1-linearity and target. By [F1] each (h~)∗ is a Λ1-module automorphism of the free module Mred of rank n−1; its matrix in the fixed basis is therefore an invertible matrix over Λ1, i.e. an element of GL⁡n−1(Λ1), with inverse the matrix of (h~−1)∗. This proves that ρˉn is a well-defined group homomorphism into GL⁡n−1(Λ1). AC enters only through the mapping-class identification and the lift of [F1].

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