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A block idempotent corner outside the stable range

Example

Assume the inherited Axiom of Choice. Take the pyramid λ=(1,1), so n=2, l=1, q1=2 and N=2, and let d=3. The stable range ql≥d fails, since 2<3; the equivalent source condition is that at least 3 parts of λ are equal to l=1, which is false. With the origin c=(0) one has a1=c1+q1−n=0, so the level-one cyclotomic quotient is H3(Λ)=C[S3], of dimension 6, while the image H3(λ,c) in End⁡C(V⊗3)op, V=C2, has dimension 5. The example identifies the image as a block idempotent corner fC[S3]f, verifying the central-corner statement of Stable range and block idempotent corner for higher-level Schur-Weyl duality in the smallest non-stable case.

Facts & Assumptions

Given: The pyramid λ=(1,1), the natural gl2-module V=C2, the tensor space V⊗3, and the group algebra C[S3].

[F1]

For this pyramid l=1, q1=2, e=0, ge=gl2 and the level-one cyclotomic quotient is H3(Λ)=C[S3] with its place-permutation action on V⊗3; the stable range ql≥d becomes 2≥3, which fails (Stable range and block idempotent corner for higher-level Schur-Weyl duality, The finite W and degenerate cyclotomic Hecke actions satisfy a double centralizer).

[F2]

The S3-module V⊗3 has a four-dimensional invariant space, with basis the symmetrizations of v13,v12v2,v1v22,v23. Its sign space is zero by [F4]. By [F3] the remaining four dimensions are two copies of the two-dimensional standard module. Thus its group-algebra image is C×M2(C), of dimension five; classical Schur-Weyl duality identifies that image with the gl2 commutant (The Schur-Weyl mutual centralizer theorem on tensor powers).

[F3]

Wedderburn decomposition C[S3]≅C×C×M2(C) with the trivial, sign and standard blocks, indexed by the partitions (3), (1,1,1) and (2,1) (If k is algebraically closed and char⁡k∤∣G∣, then k[G]≅∏i=1rMni(k), Specht modules classify the complex irreducibles of Sn).

[F4]

For dim⁡V=2 one has Λ3V=0, so the antisymmetrizer a=∑w∈S3sgn⁡(w)w acts on V⊗3 as the antisymmetrization, which is 3!=6 times the projection onto Λ3V=0; hence a acts by 0.

Proof

technique · direct

Given: The image ψ3(C[S3])⊆End⁡(V⊗3)op and the Wedderburn blocks of [F3].

1.1F2F3algebra

By [F2], the tensor space contains the trivial S3 module with multiplicity four, the standard module with multiplicity two, and no sign module. The decomposition [F3] therefore makes the group-algebra image exactly C×M2(C), of dimension five. By classical Schur-Weyl duality [F2] this is End⁡gl2(V⊗3), whereas dim⁡C[S3]=6.

2.1F3F4step 1.1algebra

The killed sign block. By [F3] the block decomposition of C[S3] is C×C×M2(C); the one-dimensional sign block is spanned by the antisymmetrizer a of [F4], which acts on V⊗3 by 0. Hence the kernel of ψ3 contains the sign block; since the image has dimension 5 by step 1.1, the kernel has dimension 1 and is exactly the sign block. So ψ3 kills precisely the sign block and is injective on the direct sum of the trivial and standard blocks.

3.1F3step 2.1algebra

The block idempotent corner. Let f be the central idempotent of the trivial and standard blocks, so that C[S3]f=C[S3]f2 is the corresponding two-sided ideal; its corner fC[S3]f has dimension 1+4=5 by [F3]. Multiplication by f, x↦fxf, is an algebra surjection C[S3]↠fC[S3]f whose kernel contains the sign block and has dimension 6−5=1, hence is exactly the sign block; therefore C[S3]/ ⁣ker⁡ψ3≅fC[S3]f and the image H3(λ,c)=ψ3(C[S3]) is isomorphic to the block idempotent corner fC[S3]f, which is the central-corner form fH3(a)f of the Definition.

4.1F1step 1.1step 3.1algebra∎

The stable-range check. Here ql=q1=2 while d=3, so the stable range fails and the image is not the full algebra H3(a)=C[S3] (which has dimension 6); the corner of step 3.1 realizes the boundary case of the Definition, and the missing dimension 1 is precisely the killed sign block.

Remarks

  • The example is the level-one, two-dimensional instance of the general corner statement: the stable range fails by one step, and the failure is visible as the dimension drop 6−5=1 caused by the vanishing Λ3C2=0.
  • The nonadmissible origin c=(0,1) example of The finite W and degenerate cyclotomic Hecke actions satisfy a double centralizer is a different boundary: here the origin is admissible and the corner is a sum of entire central blocks, as required.

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