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ExampleConstruction: AI-adaptedVerification: AI-generatedSession-authored (Fable 5 assisted)precheck passaudited 2026-07-31
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All kk-sets through a fixed point form an intersecting family attaining the Erdős-Ko-Rado bound

Example

Let AA be an nn-element set with 1k1\le k and n2kn\ge2k, and fix aAa\in A. The star

Sa={S[A]k:aS}\mathcal S_a=\{S\in[A]^k:a\in S\}

is intersecting and has cardinality (n1k1)\binom{n-1}{k-1}, attaining the Erdős-Ko-Rado bound.

Facts & Assumptions

Given: An nn-element set AA, natural numbers 1k1\le k and n2kn\ge2k, and a point aAa\in A.

[L1]

Erdős-Ko-Rado bounds an intersecting family of kk-subsets by (n1k1)\binom{n-1}{k-1} and states that a star attains the bound (Erdős-Ko-Rado theorem: for 1k1\le k and n2kn\ge 2k, an intersecting family of kk-subsets of an nn-set has size at most (n1k1)\binom{n-1}{k-1}, and a star attains the bound).

Verification

technique · direct
1.1

Any two members of Sa\mathcal S_a intersect at aa, so the star is intersecting.

given
1.2

The map SS{a}S\mapsto S\setminus\{a\} is a bijection from Sa\mathcal S_a to the (k1)(k-1)-subsets of A{a}A\setminus\{a\}. Hence Sa=(n1k1)|\mathcal S_a|=\binom{n-1}{k-1}.

givenF1
2.1

By [L1], step 1.2 equals the universal upper bound, so the star is extremal.

step 1.1step 1.2L1

Depends on

Used by

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Sources