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ExampleConstruction: AI-adaptedVerification: AI-generatedSession-authored (Fable 5 assisted)precheck passjudge pass (z-ai/glm-5.2)audited 2026-07-26
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  • Literature-sourced — the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted — a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
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Every nondegenerate closed interval is perfect, giving a second proof that it is uncountable

Example

Let a,bRa, b \in \mathbb{R} with a<ba < b. Then the closed interval E:=[a,b]E := [a,b] (Intervals of R\mathbb{R}: the nine order-convex forms, nondegeneracy, and length) is perfect (Perfect subset of R\mathbb{R}: closed with no isolated points), and therefore uncountable by Every nonempty perfect subset of R\mathbb{R} is uncountable.

This is a second proof of the uncountability of a nondegenerate interval. The first, Every nondegenerate interval of R\mathbb{R} is uncountable, runs a trisection argument directly against an assumed enumeration; the route here checks two purely local properties, closedness and the absence of isolated points, and lets the perfect-set theorem do the counting.

Facts & Assumptions

Given: Reals a<ba < b and the interval E:=[a,b]={x:axb}E := [a,b] = \{\, x : a \le x \le b \,\}.

[L1]

A set is perfect when it is closed and no point of it is isolated in it; xPx \in P is isolated in PP when some Nε(x)N_\varepsilon(x) meets PP only in xx (Perfect subset of R\mathbb{R}: closed with no isolated points, Limit point, isolated point, adherent point, derived set, and dense subset of R\mathbb{R}).

[L3]

Nε(x)={y:yx<ε}N_\varepsilon(x) = \{\, y : |y - x| < \varepsilon \,\} (The ε\varepsilon-neighbourhood and the punctured ε\varepsilon-neighbourhood of a point of R\mathbb{R}, Basic properties of the absolute value).

[L4]

Every nonempty perfect subset of R\mathbb{R} is uncountable (Every nonempty perfect subset of R\mathbb{R} is uncountable).

[L5]

For a<ba < b the intervals [a,b][a,b] and (a,b)(a,b) are uncountable (Every nondegenerate interval of R\mathbb{R} is uncountable).

[L6]

Every nonempty finite set of reals has a minimum, which is one of its members (Every nonempty finite set of reals has a maximum and a minimum, Maximum and minimum of a set).

[L7]

Ordered-field arithmetic: 0<10 < 1, so 2:=1+1>02 := 1+1 > 0 and 0<d21<d0 < d \cdot 2^{-1} < d for d>0d > 0; adding a constant and multiplying by a positive preserve inequalities; the order is total and transitive (The multiplicative identity is positive, Order is preserved by adding a constant and by adding inequalities, Sign rules for products and monotonicity of multiplication, Ordered field, Complete ordered field (least-upper-bound property)). These order-arithmetic facts are stated by their sources for the strict order only; the nonstrict forms used below follow by adjoining the equality case, in which the two sides coincide.

Verification

technique · direct
1.1

EE is closed by [L2], and nonempty since aEa \in E.

L2
1.2

No point of EE is isolated in EE: let xEx \in E and let ε>0\varepsilon > 0 be real. If x<bx < b, put t:=min{ε, bx}21t := \min\{\varepsilon,\ b - x\} \cdot 2^{-1}, which is positive by [L6] and [L7], and y:=x+ty := x + t; then y>xy > x, and yx+(bx)21<by \le x + (b-x) \cdot 2^{-1} < b by [L7], while y>xay > x \ge a, so yEy \in E with yxy \ne x and yx=tε21<ε|y - x| = t \le \varepsilon \cdot 2^{-1} < \varepsilon. If x=bx = b, then x>ax > a; put t:=min{ε, ba}21>0t := \min\{\varepsilon,\ b - a\} \cdot 2^{-1} > 0 and y:=xty := x - t; then y<xby < x \le b, and yb(ba)21>ay \ge b - (b-a) \cdot 2^{-1} > a by [L7], so yEy \in E with yxy \ne x and yx=t<ε|y - x| = t < \varepsilon. In both cases Nε(x)N_\varepsilon(x) contains a point of EE other than xx, so no ε\varepsilon isolates xx.

L1L3L6L7
2.1

By steps 1.1 and 1.2 the set EE is closed with no isolated points, that is, perfect, and it is nonempty.

step 1.1step 1.2L1
3.1

By [L4] the nonempty perfect set EE is uncountable, which reproves for [a,b][a,b] the first claim of [L5] along an independent route.

step 1.1step 2.1L4L5

Remarks

Depends on

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Sources