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Every nondegenerate closed interval is perfect, giving a second proof that it is uncountable
Example
Let with . Then the closed interval (Intervals of : the nine order-convex forms, nondegeneracy, and length) is perfect (Perfect subset of : closed with no isolated points), and therefore uncountable by Every nonempty perfect subset of is uncountable.
This is a second proof of the uncountability of a nondegenerate interval. The first, Every nondegenerate interval of is uncountable, runs a trisection argument directly against an assumed enumeration; the route here checks two purely local properties, closedness and the absence of isolated points, and lets the perfect-set theorem do the counting.
Facts & Assumptions
Given: Reals and the interval .
A set is perfect when it is closed and no point of it is isolated in it; is isolated in when some meets only in (Perfect subset of : closed with no isolated points, Limit point, isolated point, adherent point, derived set, and dense subset of ).
Each interval of the form is a closed set (Open subset of (every point has a neighbourhood inside it), closed subset (complement open), and clopen, Intervals of : the nine order-convex forms, nondegeneracy, and length).
Every nonempty perfect subset of is uncountable (Every nonempty perfect subset of is uncountable).
For the intervals and are uncountable (Every nondegenerate interval of is uncountable).
Every nonempty finite set of reals has a minimum, which is one of its members (Every nonempty finite set of reals has a maximum and a minimum, Maximum and minimum of a set).
Ordered-field arithmetic: , so and for ; adding a constant and multiplying by a positive preserve inequalities; the order is total and transitive (The multiplicative identity is positive, Order is preserved by adding a constant and by adding inequalities, Sign rules for products and monotonicity of multiplication, Ordered field, Complete ordered field (least-upper-bound property)). These order-arithmetic facts are stated by their sources for the strict order only; the nonstrict forms used below follow by adjoining the equality case, in which the two sides coincide.
Verification
is closed by [L2], and nonempty since .
No point of is isolated in : let and let be real. If , put , which is positive by [L6] and [L7], and ; then , and by [L7], while , so with and . If , then ; put and ; then , and by [L7], so with and . In both cases contains a point of other than , so no isolates .
By steps 1.1 and 1.2 the set is closed with no isolated points, that is, perfect, and it is nonempty.
By [L4] the nonempty perfect set is uncountable, which reproves for the first claim of [L5] along an independent route.
Remarks
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Nondegeneracy is exactly what is needed. For the set is closed, its single point is isolated, and it is finite; the argument of step 1.2 breaks precisely there, since neither nor holds. This matches the hypothesis of Every nondegenerate interval of is uncountable.
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The open interval supplies only half of the definition. The computation of step 1.2 applies verbatim inside and shows it has no isolated points, but is not closed, so it is not perfect. Perfectness needs both halves, which is why the example is stated for the closed interval.
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Two proofs of one fact, sharing one ingredient. Both routes spend the completeness of exactly once, Every nondegenerate interval of is uncountable as a supremum and Every nonempty perfect subset of is uncountable through A nested sequence of nonempty closed bounded intervals has nonempty intersection, and the intersection is a single point exactly when the lengths tend to . They differ in everything else: the first trisects a given interval against a given enumeration, the second selects rational-endpoint intervals by least index. Neither is a corollary of the other.
Depends on
- Perfect subset of $\mathbb{R}$: closed with no isolated points
- Every nonempty perfect subset of $\mathbb{R}$ is uncountable
- Every nondegenerate interval of $\mathbb{R}$ is uncountable
- Intervals of $\mathbb{R}$: the nine order-convex forms, nondegeneracy, and length
- Limit point, isolated point, adherent point, derived set, and dense subset of $\mathbb{R}$
- The $\varepsilon$-neighbourhood and the punctured $\varepsilon$-neighbourhood of a point of $\mathbb{R}$
- Open subset of $\mathbb{R}$ (every point has a neighbourhood inside it), closed subset (complement open), and clopen
- Every nonempty finite set of reals has a maximum and a minimum
- Maximum and minimum of a set
- Ordered field
- Complete ordered field (least-upper-bound property)
- The multiplicative identity is positive
- Order is preserved by adding a constant and by adding inequalities
- Sign rules for products and monotonicity of multiplication
- Basic properties of the absolute value
Used by
Nothing in the library uses this result yet.
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Sources
- Perfect set (Wikipedia) (standard reference, not scraped)
- Interval (mathematics) (Wikipedia) (standard reference, not scraped)
- W. Rudin, Principles of Mathematical Analysis, 3rd ed., Ch. 2 (Thm 2.43 and its corollary) (standard reference, not scraped)