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Complex sesquilinear coercivity differs from bilinear positivity
Example
On define and . Then is sesquilinear in the convention of Bounded, coercive and symmetric sesquilinear forms (linear in the first argument, conjugate-linear in the second), bounded with , and coercive with constant because . The expression is bilinear, not conjugate-linear in the second argument, and it fails the coercivity condition: , so fails at for every . More generally is not real for , and its real part is negative, for example, at , since . Hence the conjugation in the second slot is not cosmetic: the complex Lax--Milgram hypotheses cannot be applied to this bilinear pairing , and the real bilinear convention of Bounded, coercive and symmetric sesquilinear forms is genuinely a different hypothesis. This tests exactly the convention on which The Lax--Milgram theorem and A bounded form is represented by a unique bounded operator depend, and complements the real-form sources [Si] and [H], which state real bilinear versions.
Facts & Assumptions
Given: The Hilbert space with its usual inner product and the complex modulus; the pairings and .
Sesquilinearity, boundedness and coercivity definitions: is linear in the first slot and conjugate-linear in the second with , and coercive with constant when (Bounded, coercive and symmetric sesquilinear forms, Real and complex inner-product spaces and their induced length, Hilbert space).
Scalar facts: , , and (Real and imaginary parts, complex conjugation, and modulus).
Lax--Milgram and the form-to-operator lemma are stated for sesquilinear forms in the conjugate-linear-second-slot convention (The Lax--Milgram theorem, A bounded form is represented by a unique bounded operator).
Proof
The sesquilinear form : for scalars , and , so is linear in the first argument and conjugate-linear in the second; gives the bound , and gives coercivity with .
The bilinear pairing is not of this type: , so is bilinear; but with and , , so is not conjugate-linear in the second slot.
fails coercivity: has real part , while for every ; hence fails at for every . More generally is not real unless .
Consequences: neither Lax--Milgram nor the representation lemma applies to this , since it is not sesquilinear. More generally, a complex form that is both bilinear and sesquilinear satisfies , hence is the zero form. The zero form satisfies the bounded sesquilinear hypotheses of the representation lemma; on a nonzero space it cannot be coercive, but on it is coercive with every and satisfies the Lax--Milgram form hypotheses. Thus the conjugation convention matters, with this zero-form exception.
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Sources
- Leon Simon, Lectures on Partial Differential Equations (Stanford, complete 223-page author scan) (standard reference, not scraped)
- John K. Hunter, Notes on Partial Differential Equations (UC Davis, revised 18 June 2014, complete 242-page two-quarter notes) (standard reference, not scraped)
- Haim Brezis, Functional Analysis, Sobolev Spaces and Partial Differential Equations (Springer Universitext, 2011, complete 614-page text) (standard reference, not scraped)