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A one-dimensional form attains the 1/α Lax--Milgram bound

Example

On H=C with the standard inner product and α>0, let a(u,v):=αuv‾ and let Fc(v):=cv‾ for a fixed c∈C. Then a is bounded with M=α, coercive with the same constant α, and the Lax--Milgram solution of a(u,v)=Fc(v) for all v is u=cα, since αuv‾=cv‾ for all v forces αu=c. The solution operator has norm exactly 1/α: ∥Fc∥=sup⁡∣v∣≤1∣cv‾∣=∣c∣ and ∣u∣=∣c∣/α, so ∥S∥=1α. Hence the bound of The Lax--Milgram solution operator has norm at most 1/α is attained and cannot be improved uniformly over coercive forms; this is the plan’s sharpness example and the one-dimensional model of the general estimate.

Facts & Assumptions

Given: A real α>0; the Hilbert space H=C with its usual inner product and modulus; the form a(u,v)=αuv‾; and the functional Fc(v)=cv‾ for a fixed c∈C.

[F1]

a is sesquilinear, bounded with M=α, and coercive with the same constant: ∣a(u,v)∣=α∣u∣∣v∣ and a(u,u)=α∣u∣2 (Bounded, coercive and symmetric sesquilinear forms, Real and imaginary parts, complex conjugation, and modulus, Hilbert space).

[F2]

Every conjugate-linear functional on C has the form Fc(v)=v‾ Fc(1); testing at v=1 directly determines the unique solution. The abstract comparison is The Lax--Milgram solution operator has norm at most 1/α, but no choice principle is needed for this scalar computation.

[F3]

Operator norm: ∥Fc∥=sup⁡∣v∣≤1∣cv‾∣=∣c∣ and ∥S∥=sup⁡{∥S(F)∥:∥F∥≤1} (The operator norm as the least bound and as the unit-sphere or unit-ball supremum).

Proof

1.1F1F2algebra

Direct solution: the equation a(u,v)=Fc(v) reads αuv‾=cv‾ for every v∈C. Testing with v=1 forces αu=c, that is u=c/α; conversely this u satisfies the equation for every v. The scalar equation also proves uniqueness directly.

1.2F1

Boundedness and coercivity constants: from ∣a(u,v)∣=α∣u∣∣v∣ the least bound is M=α, and coercivity holds with α since a(u,u)=α∣u∣2; no larger coercivity constant can work at u=1.

2.1F2F3step 1.1

Norms: ∥Fc∥=∣c∣ by [F3], and S(Fc)=c/α has modulus ∣c∣/α, so ∥S(Fc)∥/∥Fc∥=1/α for every c≠0; hence ∥S∥=1/α, attaining the bound of the corollary.

3.1step 1.2step 2.1∎

Conclusion: the estimate ∥S∥≤1/α is sharp and cannot be improved uniformly over bounded coercive forms on a fixed Hilbert space; the one-dimensional computation is the model of the general constant.

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