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Constant-step SGD can have a nonzero noise floor

Example

Fix 0<α≤1/4, b∈R, σ≥0, and x0∈R. For every integer horizon N≥1, take the finite probability space {−1,1}N with each sign vector assigned mass 2−N, let ξ0,…,ξN−1 be its coordinate signs, set f(x)=x2/2, and run xt+1=xt−α(xt+b+σξt). Write q=1−α. For every 0≤t≤N, the horizon-consistent moment is E[xt2]=(qtx0−b(1−qt))2+ασ22−α(1−q2t), so these moments converge as t→∞ to b2+ασ2/(2−α). In the unbiased case b=0 with σ>0, the fixed-step expected squared gradient therefore has a positive noise floor.

Under AC, two published finite-horizon bounds also apply. For b=0, if RN is chosen independently and uniformly from {0,…,N−1} on a finite extension, then E∣xRN∣2≤x02/(αN)+ασ2. For general b, the uniform average satisfies N−1∑t=0N−1E[xt2]≤x02/(αN)+(5/2)b2+ασ2.

Example references

Stochastic-gradient-descent procedure: fixes the unconstrained update applied in this example.

Independent finite random-index extension: constructs the independent uniform output index.

Published uniform-random-iterate theorem: supplies the unbiased constant-step bound under its exact hypotheses.

Published biased-noise-floor theorem: supplies the bounded-bias average bound under its exact hypotheses.

Facts & Assumptions

Given: The finite product sample space and recurrence in the Example; AC is used only for the two conditional-expectation theorem comparisons at the end of the verification.

[A1]

The Axiom of Choice: AC supplies the conditional-expectation classes required by the published theorem comparisons.

[F1]

Stochastic gradient descent: for s=1,…,N, the update is ys+1=ys−αHs, starting at y1.

[F2]

Probability measures and probability spaces and Measures on sigma-algebras: a probability measure has total mass one and is countably additive.

[F3]

Random elements and real random variables: each coordinate sign is a measurable real random variable.

[F4]

Filtration and filtered probability space and Adapted and integrable stochastic process: Ft records the first t signs and xt is measurable with respect to it.

[F5]

Conditional expectation as an ae class: conditional expectations are almost-sure classes under AC.

[F6]

Conditional variance and Conditional variance is well-defined and has the second-moment formula: conditional variance is the conditional second moment of the centered direction.

[F8]

An independent finite random index has the weighted expectation formula: a finite uniform index can be added independently and its output expectation is the arithmetic mean of the iterate expectations.

[F9]

Nonconvex SGD stationarity bound for a uniform randomized iterate: assume AC, f:Rd→R continuously differentiable with L-Lipschitz gradient for L>0, a real global lower bound finf⁡, deterministic x0, and the filtration-adapted update with square-integrable directions, conditional mean ∇f(xt) and conditional variance at most σ2. For constant 0<α≤1/L, N≥1, and Δ=f(x0)−finf⁡, the independent uniform output from {0,…,N−1} obeys E∥∇f(xR)∥22≤2Δ/(αN)+Lασ2.

[F10]

Biased SGD has an explicit weighted stationarity floor: assume AC, f:Rd→R with L-Lipschitz gradient for L>0, a real global lower bound finf⁡, square-integrable x0, and the filtration-adapted update with square-integrable directions, conditional mean ∇f(xt)+bt, measurable conditional bias bt of norm at most a deterministic β≥0, and conditional variance at most a deterministic σ2≥0. For constant 0<α≤1/(4L), N≥1, and finite Δ=Ef(x0)−finf⁡, the uniform average of E∥∇f(xt)∥22 over 0≤t<N is at most 2Δ/(αN)+(5/2)β2+Lασ2.

[F11]

Expectation of a nonnegative or integrable random variable: expectation on a finite probability space is the finite weighted sum.

Verification

1.1F1F2F3F4F11givenconstructalgebra

For a fixed horizon N, let Ft be generated by ξ0,…,ξt−1, with F0 trivial and Ft=FN for t>N. Apply [F1] with ys=xs−1, Hs=Gs−1, and Hs=Fs−1 for s≥1, setting H0=F0; this gives exactly the zero-based recurrence in the Example. For 0≤t<N and each prefix atom A, define CtH on A as the average of H over its 2N−t extensions. This is an explicit Ft-measurable function, and finite summation gives ∫BCtH dP=∫BH dP for every B∈Ft, since B is a union of prefix atoms. Half the extensions of each prefix have each next sign, so Ctξt=0 and Ct(ξt2)=1. The recurrence makes xt constant on each prefix, hence CtGt=xt+b and Ct[(Gt−(xt+b))2]=σ2 for Gt=xt+b+σξt. All variables have finite moments on the finite space; these averages and identities require no AC.

1.2F1giveninductionalgebra

Put mt=E[xt]. The update is xt+1=qxt−αb−ασξt, hence mt+1=qmt−αb with m0=x0. Induction gives mt=qtx0−b(1−qt) for every t≤N.

2.1F2F4F11step 1.1step 1.2givenalgebra

Let Vt=E[(xt−mt)2]. Averaging first over each prefix atom as in step 1.1 gives E[(xt−mt)ξt]=0 and E[ξt2]=1, so the cross term vanishes and Vt+1=q2Vt+α2σ2, with V0=0. Thus Vt=α2σ2∑j=0t−1q2j=ασ22−α(1−q2t), since 1−q2=α(2−α). Adding mt2 proves the displayed moment formula, and it is independent of the chosen horizon whenever N≥t.

2.2A1F5F6F8F9step 1.1givenalgebra

Now assume AC for the published bounds. The event-integral identities in step 1.1 identify its finite averages with the conditional-expectation classes [F5] and their conditional variances [F6]. Here f′(x)=x and ∣f′(u)−f′(v)∣=∣u−v∣, so the gradient is 1-Lipschitz. The deterministic start and all directions are square-integrable by step 1.1, and f(x)≥0. In the unbiased case, L=1, finf⁡=0, Δ=x02/2, and step 1.1 verifies conditional unbiasedness and variance σ2; α≤1/4≤1/L. Use [F8] with pk=1/N and apply [F9] to obtain E∣xRN∣2≤x02/(αN)+ασ2.

3.1F7step 2.1givenalgebra

Here q=1−α∈[3/4,1), so [F7] gives qt→0. The formula in step 2.1 therefore yields E[xt2]→b2+ασ2/(2−α); if b=0<σ, this limit is strictly positive. This proves the exact constant-step noise-floor claim without using AC.

4.1A1F5F6F10step 1.1step 2.2step 3.1givenalgebra∎

For general b, step 1.1 verifies conditional mean f′(xt)+b, bias bound β=∣b∣, variance bound σ2, and f(x)≥0. The step restriction is α≤1/(4L) because L=1. Apply [F10] with Δ=x02/2 to obtain N−1∑t=0N−1E[xt2]≤x02/(αN)+(5/2)b2+ασ2. The exact limiting floor from step 3.1 is at most b2+ασ2, since 2−α≥1, and is therefore consistent with this bound.

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