Alphabeta Math
ExampleConstruction: AI-adaptedVerification: AI-adaptedPipeline-generatedjudge pass (gpt-5.6-terra)audited 2026-09-13
How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

A degenerate multivariate Gaussian limit

Example

Assume AC. Let Yk be centered iid real variables of variance σ2>0 and set Xk=(Yk,Yk). Then n1/2k=1nXk(Z,Z),ZN(0,σ2). The limit covariance is Σ=σ2(1111), a singular matrix of rank one.

Facts & Assumptions

[F1]

Iid vectors with finite second moments have the Gaussian covariance limit, even if singular. Multivariate iid central limit theorem.

[F2]

A Gaussian law is characterized by its normal projections. Multivariate normal law, including singular covariance.

[F3]

The projection-defined Gaussian law is unique. Characteristic function of a multivariate normal law.

[F4]

Scalar affine images have the stated characteristic functions. Characteristic functions under affine maps and independent sums.

[F5]

Scalar normals have the specified transform and variance. Characteristic function of a normal law.

[F6]

Equal scalar characteristic functions imply equal laws under AC. Uniqueness of a law from its characteristic function.

Verification

Given: Assume AC. Let Yk be centered iid real variables of variance σ2>0 and set Xk=(Yk,Yk). Then n1/2k=1nXk(Z,Z),ZN(0,σ2). The limit covariance is Σ=σ2(1111), a singular matrix of rank one.

1.1

The vector has mean (0,0), second norm moment 2EYk2=2σ2, and each covariance entry equals EYk2=σ2. The two columns of Sigma agree and are nonzero, so its rank is one and determinant zero. Its eigenvectors (1,1) and (1,-1) have eigenvalues 2σ2 and zero. [F1] therefore gives convergence to N2(0,Σ).

F1
2.1

For a scalar ZN(0,σ2), every projection of (Z,Z) is (u1+u2)Z. By [F4]–[F6], this has law N(0,σ2(u1+u2)2), including a negative coefficient and coefficient zero. Since uTΣu=σ2(u1+u2)2, [F2]–[F3] identify (Z,Z) with the target law. It is supported on the diagonal, and the (1,-1) projection is identically zero both before and after the limit. If the optional case sigma=0 is allowed, all centered Y_k vanish almost surely and the example reduces to the point mass (0,0). AC is inherited from the Gaussian and multivariate CLT suppliers.

step 1.1F2F3F4F5F6

Depends on

Used by

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Sources