Alphabeta Math
ExampleConstruction: AI-adaptedVerification: AI-generatedprecheck passjudge pass (z-ai/glm-5.2)audited 2026-07-27
How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

The discrete and indiscrete topologies, their closures and interiors, and their continuous maps in each direction

Example

Let X be a set, let Tdisc=P(X) be the discrete topology and Tind={∅,X} the indiscrete topology (The discrete, indiscrete, cofinite, cocountable, particular-point and Sierpinski topologies), and let A⊆X. Then:

  1. In the discrete space every subset is clopen, and int⁡(A)=A=A‾,∂A=∅ for every A (Interior, closure, boundary, exterior, derived set and isolated point in a topological space). The singletons { {x}:x∈X } form a basis (Basis and subbasis for a topology, and the topology generated by a family of sets).
  2. In the indiscrete space int⁡(A)={XA=X∅A≠X,A‾={∅A=∅XA≠∅, so ∂A=X for every A other than ∅ and X.
  3. Maps out of a discrete space and into an indiscrete space are all continuous. For any topological space Y, every function (X,Tdisc)→Y is continuous, and every function Y→(X,Tind) is continuous.
  4. The other two directions are restrictive. A function f:Y→(X,Tdisc) is continuous exactly when f−1[{x}] is open in Y for every x∈X; and a function g:(X,Tind)→Y is continuous exactly when g−1[V]∈{∅,X} for every open V⊆Y.

The two topologies are the extreme points of the comparison order (Topology on a set, open and closed sets, clopen sets, the closed-set axiomatisation, and the coarser/finer comparison): every topology on X is finer than Tind and coarser than Tdisc.

Facts & Assumptions

Given: A set X with the two topologies above, a subset A⊆X, a topological space Y, and functions f:Y→X and g:X→Y.

[A1]
[A2]

int⁡(A) is the largest open subset of A and A‾ the smallest closed superset of A; ∂A=A‾∖int⁡(A); a set is closed exactly when its complement is open (Interior, closure, boundary, exterior, derived set and isolated point in a topological space, Topology on a set, open and closed sets, clopen sets, the closed-set axiomatisation, and the coarser/finer comparison).

[L1]

A map is continuous exactly when preimages of open sets are open, and exactly when preimages of the members of any fixed basis are open, a basis being a subbasis for the topology it generates (For a map of spaces the following agree: continuity at every point, preimages of open sets open, preimages of closed sets closed, preimages of subbasic open sets open, and f(A‾)⊆f(A)‾, clauses (b) and (d), Continuity of a map of topological spaces at a point and globally).

[L2]

A family B of subsets of X is a basis for a topology exactly when it covers X and every point of an intersection of two members lies in a member inside that intersection; the topology is then the family of unions of subfamilies (A family is a basis for a unique topology iff it covers the set and every point of an intersection of two members lies in a member inside that intersection; finite intersections of any subbasis form a basis, Basis and subbasis for a topology, and the topology generated by a family of sets).

Verification

technique · direct
1.1

In the discrete topology every subset of X is open by [A1], so every subset is also closed, its complement being open; hence every subset is clopen.

A1A2
1.2

The singletons cover X, and the intersection of two distinct singletons is empty while the intersection of a singleton with itself is that singleton; so the family of singletons satisfies the basis criterion, and the topology it generates consists of all unions of singletons, that is of all subsets of X, which is Tdisc.

A1L2
1.3

In the indiscrete topology the open subsets of A are ∅ always and X exactly when A=X; so int⁡(A)=X if A=X and int⁡(A)=∅ otherwise.

A1A2
1.4

In the indiscrete topology the closed sets are ∅ and X, so the closed supersets of A are X always and ∅ exactly when A=∅; hence A‾=∅ if A=∅ and A‾=X otherwise.

A1A2
1.5

For any function h out of the discrete space and any open V in the target, h−1[V] is a subset of X and hence open; for any function h into the indiscrete space, the only open sets of the target are ∅ and X, whose preimages are ∅ and the whole source, both open.

A1L1
2.1

For f:Y→(X,Tdisc): the singletons form a basis by step 1.2, so by clause (d) of [L1] continuity of f is exactly the openness of every f−1[{x}]. For g:(X,Tind)→Y: by clause (b) continuity is exactly the condition that each g−1[V] be open in the indiscrete topology, that is a member of {∅,X}.

step 1.2A1L1
2.2

By step 1.1 every A⊆X is open and closed in the discrete topology, so int⁡(A)=A and A‾=A by [A2], whence ∂A=∅; with step 1.2 this is claim 1.

step 1.1step 1.2A2
2.3

Steps 1.3 and 1.4 are claim 2, and for A∉{∅,X} they give ∂A=X∖∅=X.

step 1.3step 1.4A2
3.1

Step 1.5 is claim 3 and step 2.1 is claim 4.

step 1.5step 2.1∎

Remarks

Depends on

Used by

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Dependency tree · two levels

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Sources