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ExampleConstruction: AI-adaptedVerification: AI-generatedSession-authored (Fable 5 assisted)precheck passjudge pass (z-ai/glm-5.2)audited 2026-07-27
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  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

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The discrete and indiscrete topologies, their closures and interiors, and their continuous maps in each direction

Example

Let XX be a set, let Tdisc=P(X)\mathcal{T}_{\mathrm{disc}} = \mathcal{P}(X) be the discrete topology and Tind={,X}\mathcal{T}_{\mathrm{ind}} = \{\varnothing, X\} the indiscrete topology (The discrete, indiscrete, cofinite, cocountable, particular-point and Sierpinski topologies), and let AXA \subseteq X. Then:

  1. In the discrete space every subset is clopen, and int(A)=A=A,A=\operatorname{int}(A) = A = \overline{A}, \qquad \partial A = \varnothing for every AA (Interior, closure, boundary, exterior, derived set and isolated point in a topological space). The singletons {{x}:xX}\{\, \{x\} : x \in X \,\} form a basis (Basis and subbasis for a topology, and the topology generated by a family of sets).
  2. In the indiscrete space int(A)={XA=XAX,A={A=XA,\operatorname{int}(A) = \begin{cases} X & A = X \\ \varnothing & A \ne X \end{cases}, \qquad \overline{A} = \begin{cases} \varnothing & A = \varnothing \\ X & A \ne \varnothing \end{cases}, so A=X\partial A = X for every AA other than \varnothing and XX.
  3. Maps out of a discrete space and into an indiscrete space are all continuous. For any topological space YY, every function (X,Tdisc)Y(X, \mathcal{T}_{\mathrm{disc}}) \to Y is continuous, and every function Y(X,Tind)Y \to (X, \mathcal{T}_{\mathrm{ind}}) is continuous.
  4. The other two directions are restrictive. A function f:Y(X,Tdisc)f : Y \to (X, \mathcal{T}_{\mathrm{disc}}) is continuous exactly when f1[{x}]f^{-1}[\{x\}] is open in YY for every xXx \in X; and a function g:(X,Tind)Yg : (X, \mathcal{T}_{\mathrm{ind}}) \to Y is continuous exactly when g1[V]{,X}g^{-1}[V] \in \{\varnothing, X\} for every open VYV \subseteq Y.

The two topologies are the extreme points of the comparison order (Topology on a set, open and closed sets, clopen sets, the closed-set axiomatisation, and the coarser/finer comparison): every topology on XX is finer than Tind\mathcal{T}_{\mathrm{ind}} and coarser than Tdisc\mathcal{T}_{\mathrm{disc}}.

Facts & Assumptions

Given: A set XX with the two topologies above, a subset AXA \subseteq X, a topological space YY, and functions f:YXf : Y \to X and g:XYg : X \to Y.

[A1]

Tdisc=P(X)\mathcal{T}_{\mathrm{disc}} = \mathcal{P}(X) and Tind={,X}\mathcal{T}_{\mathrm{ind}} = \{\varnothing, X\} (The discrete, indiscrete, cofinite, cocountable, particular-point and Sierpinski topologies).

[A2]

int(A)\operatorname{int}(A) is the largest open subset of AA and A\overline{A} the smallest closed superset of AA; A=Aint(A)\partial A = \overline{A} \setminus \operatorname{int}(A); a set is closed exactly when its complement is open (Interior, closure, boundary, exterior, derived set and isolated point in a topological space, Topology on a set, open and closed sets, clopen sets, the closed-set axiomatisation, and the coarser/finer comparison).

[L1]

A map is continuous exactly when preimages of open sets are open, and exactly when preimages of the members of any fixed basis are open, a basis being a subbasis for the topology it generates (For a map of spaces the following agree: continuity at every point, preimages of open sets open, preimages of closed sets closed, preimages of subbasic open sets open, and f(A)f(A)f(\overline{A}) \subseteq \overline{f(A)}, clauses (b) and (d), Continuity of a map of topological spaces at a point and globally).

[L2]

A family B\mathcal{B} of subsets of XX is a basis for a topology exactly when it covers XX and every point of an intersection of two members lies in a member inside that intersection; the topology is then the family of unions of subfamilies (A family is a basis for a unique topology iff it covers the set and every point of an intersection of two members lies in a member inside that intersection; finite intersections of any subbasis form a basis, Basis and subbasis for a topology, and the topology generated by a family of sets).

Verification

technique · direct
1.1

In the discrete topology every subset of XX is open by [A1], so every subset is also closed, its complement being open; hence every subset is clopen.

A1A2
1.2

The singletons cover XX, and the intersection of two distinct singletons is empty while the intersection of a singleton with itself is that singleton; so the family of singletons satisfies the basis criterion, and the topology it generates consists of all unions of singletons, that is of all subsets of XX, which is Tdisc\mathcal{T}_{\mathrm{disc}}.

A1L2
1.3

In the indiscrete topology the open subsets of AA are \varnothing always and XX exactly when A=XA = X; so int(A)=X\operatorname{int}(A) = X if A=XA = X and int(A)=\operatorname{int}(A) = \varnothing otherwise.

A1A2
1.4

In the indiscrete topology the closed sets are \varnothing and XX, so the closed supersets of AA are XX always and \varnothing exactly when A=A = \varnothing; hence A=\overline{A} = \varnothing if A=A = \varnothing and A=X\overline{A} = X otherwise.

A1A2
1.5

For any function hh out of the discrete space and any open VV in the target, h1[V]h^{-1}[V] is a subset of XX and hence open; for any function hh into the indiscrete space, the only open sets of the target are \varnothing and XX, whose preimages are \varnothing and the whole source, both open.

A1L1
2.1

For f:Y(X,Tdisc)f : Y \to (X,\mathcal{T}_{\mathrm{disc}}): the singletons form a basis by step 1.2, so by clause (d) of [L1] continuity of ff is exactly the openness of every f1[{x}]f^{-1}[\{x\}]. For g:(X,Tind)Yg : (X,\mathcal{T}_{\mathrm{ind}}) \to Y: by clause (b) continuity is exactly the condition that each g1[V]g^{-1}[V] be open in the indiscrete topology, that is a member of {,X}\{\varnothing, X\}.

step 1.2A1L1
2.2

By step 1.1 every AXA \subseteq X is open and closed in the discrete topology, so int(A)=A\operatorname{int}(A) = A and A=A\overline{A} = A by [A2], whence A=\partial A = \varnothing; with step 1.2 this is claim 1.

step 1.1step 1.2A2
2.3

Steps 1.3 and 1.4 are claim 2, and for A{,X}A \notin \{\varnothing, X\} they give A=X=X\partial A = X \setminus \varnothing = X.

step 1.3step 1.4A2
3.1

Step 1.5 is claim 3 and step 2.1 is claim 4.

step 1.5step 2.1

Remarks

Depends on

Used by

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Dependency tree · next 3 levels

Direct dependencies and their dependencies through the next three levels: 41 results over 17 levels. An arrow runs from a result to what uses it, and this result sits at the bottom with a heavier outline. Click the chart to enlarge it.

Sources