Alphabeta Math
ExampleConstruction: Literature-sourcedVerification: AI-adaptedPipeline-generatedjudge pass (gpt-5.6-terra)audited 2026-09-14
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A dyadic martingale converges to the original L1 variable

Statement

Assume AC. On ([0,1],B,λ), let Fn be generated by the dyadic half-open intervals of length 2n, using ((j1)2n,j2n] and the null singleton {0}. For every XL1, Mn=E[XFn]X almost surely and in L1.

Facts & Assumptions

Given: The hypotheses, objects, and conventions in the Statement.

[F2]

Levy upward convergence of conditional expectations gives the limit along an increasing filtration.

[F3]

Conditioning a known variable and an independent variable identifies conditioning a measurable variable with itself.

[F4]

The Axiom of Choice is inherited from conditional expectation.

Proof

1.1

Every positive-length level-n cell is the union of its two level-(n+1) children, while the singleton {0} is itself a generator at every level. Hence FnFn+1. Dyadic half-open intervals form a countable base for the relative topology of [0,1]: every open interval is the countable union of dyadic cells whose closures lie inside it, with endpoints handled by the stated convention. Thus F1 gives σ(nFn)=B.

F1
2.1

F2 gives MnE[XB] almost surely and in L1. Since X is B-measurable, F3 identifies the latter conditional expectation with X. The singleton endpoint convention changes no L1 or almost-sure statement. AC is used exactly through F4.

F2F3F4step 1.1

Depends on

Used by

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Sources