Alphabeta Math
ExampleConstruction: Literature-sourcedVerification: AI-adaptedSession-authored (Fable 5 assisted)precheck passaudited 2026-08-11
How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

Euler's formula checked on a plane tree, a cycle, and the four-face embedding of K4K_4

Example

Euler's formula gives the same value on a plane tree, a cycle, and the tetrahedral embedding of K4K_4.

Facts & Assumptions

Given: A plane tree on n1n\ge1 vertices, a plane cycle on n3n\ge3 vertices, and the standard plane embedding of K4K_4.

[L1]

Every connected plane graph satisfies VE+F=2|V|-|E|+|F|=2 (Euler's formula VE+F=2|V|-|E|+|F|=2 for every connected plane graph).

[L2]

A finite forest satisfies V=E+c|V|=|E|+c, so a tree on nn vertices has n1n-1 edges (For every forest, V=E+c|V|=|E|+c, where cc is the number of connected components).

Verification

technique · direct
1.1

By [L2], a tree on nn vertices has n1n-1 edges, and its plane embedding has one face by Every plane forest has exactly one face. Thus VE+F=n(n1)+1=2|V|-|E|+|F|=n-(n-1)+1=2. This includes the one-vertex tree, for which the edge count is zero.

L1L2algebra
1.2

A plane cycle CnC_n, in the notation of Empty and complete graphs, complete bipartite graphs, and the convention that PnP_n and CnC_n have nn vertices, has nn vertices and nn edges. Its polygon bounds one face and has the unbounded face on the other side, so VE+F=nn+2=2|V|-|E|+|F|=n-n+2=2.

L1algebra
2.1

Embed three vertices of K4K_4 as a triangle and place the fourth inside it, joined to all three corners. The graph has four vertices, six edges, three bounded triangular faces, and the unbounded triangular face. Hence VE+F=46+4=2|V|-|E|+|F|=4-6+4=2, as [L1] requires.

L1constructalgebra

Depends on

Used by

Nothing in the library uses this result yet.

Dependency tree · next 3 levels

Direct dependencies and their dependencies through the next three levels: 61 results over 20 levels. An arrow runs from a result to what uses it, and this result sits at the bottom with a heavier outline. Click the chart to enlarge it.

Sources